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taurus [48]
3 years ago
6

I need help asap!!! Please and thank you

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
7 0

Answer:

4\sqrt{2}

Step-by-step explanation:

\sqrt{32}=\sqrt{16*2}=4\sqrt{2}

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True, this equation is a quadratic equation,.
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Csc α - sin α =cos α cot α<br> Show how this is an identity?
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Csc a - sin a = cos a cot a
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Therefore, the given equation is an identity.
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The scale of a map says that 6 cm represents 15 km.
atroni [7]
37.5 km is equal to 15 cm
5 0
3 years ago
Can someone help me find the equivalent expressions to the picture below? I’m having trouble
miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is \frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}.

Now we will solve this expression with the help of law of exponents.

\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}

           =2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}

           =2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}

           =2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}

           =2^{\frac{2}{9}}\times 3^{-\frac{2}{3} } [Option 2]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2 [Option 1]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2

                =(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }

                =\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} } [Option 3]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }

               =\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}} [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0
3 years ago
2. Kerry has a $1,973-per-month mortgage payment. He decides to refinance his $204,000 balance at 5% over 20 years. What's his n
klemol [59]

The formula for the amount of a monthly payment A on principal amount P at interest rate i loaned for t years is given by

... A = P(i/12)/(1 -(1 +i/12)^(-12t))

Filling in the given values, this is

... A = $204000(.05/12)/(1 -(1 +.05/12)^(-12·20)) ≈ $1346.31

5 0
3 years ago
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