Left Panel
A is an acid. Not the answer.
B is correct. That would be a base. But it is not an Arrhenius base. Keep reading.
C that is exactly what an Arrhenius base is.
D. No an acid of some sort would accept OH ions.
Right Panel
D is concentrated and it is also a weak base. Good cleaning fluid. Smells awful but it works.
I need more characters but it is b
Answer:
Keq = 0.053
7.3 kJ/mol
Explanation:
Let's consider the following isomerization reaction.
glucose 6‑phosphate ⇄ glucose 1 - phosphate
The concentrations at equilibrium are:
[G6P] = 0.19 M
[G1P] = 0.01 M
The concentration equilibrium constant (Keq) is:
Keq = [G1P] / [G6P]
Keq = 0.01 / 0.19
Keq = 0.053
We can find the standard free energy change, ΔG°, of the reaction mixture using the following expression.
ΔG° = -R × T × lnKeq
ΔG° = -8.314 J/mol.K × 298 K × ln0.053
ΔG° = 7.3 × 10³ J/mol = 7.3 kJ/mol
Answer:
Explanation:
Hello,
In this case, since the nowadays concentration of CO2 is 414.51 ppm and the concentration in 1958 was 315.71 ppm, the total increase is computed via the difference between them:
Moreover, the average increase per year is computed considering that from 1958 to 2020, 62 years have passed, therefore, such average is:
Regards.
