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dimaraw [331]
3 years ago
12

Please help brainiest is award!

Chemistry
2 answers:
andrey2020 [161]3 years ago
6 0
The answer is b good luck
Elodia [21]3 years ago
4 0
I need more characters but it is b
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What do I scan to confirm that a book is relevant and valuable as a source
Elden [556K]
It's genre. Look for something either on a final or starting page near the cover, and check to look if it's non fiction, or anything else that could prove it as reliable.
7 0
3 years ago
An equilibrium mixture contains 0.750 mol of each of the products (carbon dioxide and hydrogen gas) and 0.200 mol of each of the
sasho [114]

1.302  moles of carbon dioxide would have to be added

<h3>Further explanation</h3>

The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient

The equilibrium constant is based on the concentration (Kc) in a reaction

pA + qB -----> mC + nD

\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}

While the equilibrium constant is based on partial pressure

\large {\boxed {\bold {Kp ~ = ~ \frac {[pC] ^ m [pD] ^ n} {[pA] ^ p [pB] ^ q}}}}

The value of Kp and Kc can be linked to the formula '

\large {\boxed {\bold {Kp ~ = ~ Kc. (R.T) ^ {\Delta n}}}}

R = gas constant = 0.0821 L.atm / mol.K

=n = number of product coefficients-number of reactant coefficients

An equilibrium mixture: 0.750 moles of CO2 and H2, and 0.200 moles of CO and H2O

  • We determine Kc (constant concentration)

\displaystyle Kc=\frac{0.75.0.75}{0.2.0.2}\\\\Kc=14.1

  • the amount of carbon monoxide to 0.300 mol

Reaction :

                CO +H₂O ⇔ CO₂ + H₂

initially      0.2   0.2       0.75+x  0.75

reaction    0.1    0.1        0.1         0.1

product     0.3   0.3       0.65+x    0.65

\displaystyle Kc=\frac{(0.650+x)(0.65)}{0.3.0.3}\\\\14.1(0.09)=0.4225+0.65x\\\\1.269-0.4225=0.65x\\\\0.8465=0.65x\\\\x=1.302

<h3>Learn more</h3>

an equilibrium constant brainly.com/question/9173805

brainly.com/question/1109930

Calculate the value of the equilibrium constant, Kc

brainly.com/question/3612827

Concentration of hi at equilibrium

brainly.com/question/8962129

Keywords: constant equilibrium, Kc, concentration, product, reactant, reaction coefficient

3 0
4 years ago
Read 2 more answers
When sodium chloride, NaCl , dissolves in water, the solution contains ___________________ in addition to the water solvent. The
g100num [7]

Answer:

sodium ions and chloride ions

chloride ion

sodium ion

Explanation:

Ionic substances are composed of ions. When you dissolve an Ionic substance in water, the ions that compose the substance together with water molecules are present in solution.

Hence, when sodium chloride is dissolved in water, sodium ions and chloride ions are released in solution.

Water has a dipole moment. Hence, the chloride ions are attracted to hydrogen (the positive end of the dipole) while sodium ions are attracted to oxygen (the negative end of the dipole).

This is how the solid is dissolved in water.

4 0
3 years ago
Which one of the following substances is a liquid fuel used in rocket engines?
kotegsom [21]

Must be C because the liquid fuel is Codium nitrate to be used in rocket engines

6 0
3 years ago
Read 2 more answers
Which of the following conversion factors is correct to convert 0.25 moles of Na to particles of Na?
Stolb23 [73]

Answer:

6.02×10²³ particles / 1 mol

Explanation:

In this question the choices are missed.

For determine the particles of Na, in 0.25 moles we should know that the mole referrs to the Avogadro's number.

1 mol of anything contains 6.02×10²³ entities, that's why we should apply this conversion factor to find the final answer:

0.25 mol . 6.02×10²³ particles / 1 mol = 1.50×10²³ particles

In conclussion: 1.50×10²³ particles of Na are contained in 0.25 moles of Na

5 0
4 years ago
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