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Y_Kistochka [10]
3 years ago
10

Phosphoglucoisomerase interconverts glucose 6‑phosphate to, and from, glucose 1‑phosphate.

Chemistry
1 answer:
lawyer [7]3 years ago
7 0

Answer:

Keq = 0.053

7.3 kJ/mol

Explanation:

Let's consider the following isomerization reaction.

glucose 6‑phosphate ⇄ glucose 1 - phosphate

The concentrations at equilibrium are:

[G6P] = 0.19 M

[G1P] = 0.01 M

The concentration equilibrium constant (Keq) is:

Keq = [G1P] / [G6P]

Keq = 0.01 / 0.19

Keq = 0.053

We can find the standard free energy change, ΔG°, of the reaction mixture using the following expression.

ΔG° = -R × T × lnKeq

ΔG° = -8.314 J/mol.K × 298 K × ln0.053

ΔG° = 7.3 × 10³ J/mol = 7.3 kJ/mol

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A leaf change color is evidence of which type of chemical change?
garri49 [273]

Answer:

changes like leaves turning color in the fall are chemical changes. They involve chemical reactions. Bonds break in chemicals and new bonds form. Substances change into new chemical compounds.

Explanation:

6 0
3 years ago
Why is the chemical formula magnesium sulfide written as MgS and NOT Mg2S2?
Anna71 [15]

Explanation:

The chemical formula magnesium sulfide written as MgS and NOT Mg_{2}S_{2} because charge on magnesium ion is +2 and charge on sulfide ion is -2.

Therefore, these charges will cancel out each other as we write the formula in simplest crisscross  method.

Also, the numbers in a chemical formula display the total number of atoms attached with each other or central atom.

For example, in CaCl_{2} there are two chlorine atoms attached to one calcium atom.

Therefore, MgS denotes one sulfur atom is attached to magnesium atom. Hence, we do not write the formula of magnesium sulfide as Mg_{2}S_{2} because this shows two magnesium atoms are attached to two sulfur atoms which is not true.

8 0
3 years ago
Read 2 more answers
Calculate the new boiling point of a solution if 10.00 g of a non-ionizing compound (C3H5(OH)3) is dissolved in 90.00 g of H2O.
erma4kov [3.2K]

Answer:

Boiling T° of solution = 100.6

Explanation:

Formula for elevation of boiling point is:

ΔT = Kb . m . i

where ΔT means Boiling T° of solution - Boiling T° of pure solvent

Our solute is a non ionizing compound.

i = 1, because it is a non ionizing compound. i, indicates the ions dissolved in solution.

m = molality (moles of solute dissolved in 1 kg of solvent)

90 g of solvent = 0.09 kg of solvent

We convert mass of solute to moles (by the molar mass):

10 g . 1 mol /92.09 g = 0.108 moles

m = 0.108 mol /0.09 kg = 1.21 m

Let's replace data: Boiling T° of solution - 100°C = 0.51 °C/m . 1.21 m . 1

Boiling T° of solution = 0.51 °C/m . 1.21 m . 1 + 100°C

Boiling T° of solution = 100.6

5 0
3 years ago
What mass of magnesium chloride is needed to make 100.0 mL of a solution that is 0.500 M in chloride ion?
miss Akunina [59]
M = n/V

.5M = n/.100 L

n = .1 L * .5M

n= .05 mols of MgCl2

mass of MgCl2 = .05 mols of MgCl2 * 95.211 grams/ 1 mol of MgCl2 

mass of MgCl2 = 4.76 grams

4.76 grams of MgCl2 is needed to make 100 ml of a solution that is .500M, in chloride ion. Bolded = confused
3 0
3 years ago
A beach ball has a mass of 5 g and a volume of 20 cm3. What is the object's density?
ivann1987 [24]
Mass = 5 g

volume = 20 cm³

density = mass / volume

therefore:

D = m / V

D = 5 / 20

D = 0.25 g/cm³
3 0
3 years ago
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