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3 years ago

To achieve the human resource management goal of promoting individual growth and development, organizations should:

Business

1 answer:

Ivahew [28]3 years ago

5 0

Answer:

implement wide range of human engagement activities

Explanation:

In order to increase or at-least maintain the individual growth in any organisation the company shall engage each and every human in various activities.

This not only ensures human engagement in the company, but also a mental and physical boost to the employees.

When an employee is involved in several areas or activities he considers himself to be of vital importance as the organisation considers his views in various areas.

Further with multiple areas to perform the employee enhances his capacities and areas to grow as an individual.

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The ___ act requires companies to produce both an internal control report and an external audit.

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Answer:

b :)

Explanation:

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3 years ago

Read 2 more answers

Workers in the nation of Brotherton expect managers to forcefully tell employees what to do, how to do it, and when. On the othe

pogonyaev

Answer:

The answer is B. Socio-cultural

Explanation:

The socio-cultural environment refers to the beliefs, practice, customs, tradition that influences the behaviour of a people that lives in a given population.

The socio-cultural belief of the nation of Brotherton is one that believe that all the planning activities of the organisation should be the duties of manager alone and the employee are just to do as they are told.

However, the American workers participate and make contributions in the decision making process of the organisation.

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2 years ago

Holly's Ham, Inc. sells hams during the major holiday seasons. During the current year 11,000 hams were sold resulting in $220,0

yuradex [85]

I’m not sure but I think it’s A
sorry if it’s wrong

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2 years ago

How can you value our farmers in your own simple way

SOVA2 [1]

Answer:

By helping them

Explanation:

We need to cooperate

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3 years ago

Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma

Mrac [35]

Answer:

The Linear programming model is given as below

Profit Function: $P=90X+120Y+150Z$

Constraints:

$2X+2Y+Z\leq 400$

$3X+4Y+6Z\leq 240$

$4X+6Y+5Z\leq 320$

$\dfrac{2X+2Y+Z}{40}\leq 10$

$\dfrac{3X+4Y+6Z}{40}\leq 6$

$\dfrac{4X+6Y+5Z}{40}\leq 8$

$\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19$

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so the maximizing function is the profit function which is given as

$P=90X+120Y+150Z$

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

$2X+2Y+Z\leq 400$

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

$3X+4Y+6Z\leq 240$

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

$4X+6Y+5Z\leq 320$

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

$\dfrac{2X+2Y+Z}{40}\leq 10$

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

$\dfrac{3X+4Y+6Z}{40}\leq 6$

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

$\dfrac{4X+6Y+5Z}{40}\leq 8$

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

$\dfrac{2X+2Y+Z}{35}$

That of machine 2 is given as

$\dfrac{3X+4Y+6Z}{35}$

That of machine 3 is given as

$\dfrac{4X+6Y+5Z}{35}$

As the total number of workers is 19 so the constraint is given as

$\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19$

So the Linear programming model is given as below

Profit Function: $P=90X+120Y+150Z$

Constraints:

$2X+2Y+Z\leq 400$

$3X+4Y+6Z\leq 240$

$4X+6Y+5Z\leq 320$

$\dfrac{2X+2Y+Z}{40}\leq 10$

$\dfrac{3X+4Y+6Z}{40}\leq 6$

$\dfrac{4X+6Y+5Z}{40}\leq 8$

$\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19$

4 0

3 years ago