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aalyn [17]
3 years ago
9

Arona Corporation manufactures canoes in two departments, Fabrication and Waterproofing. In the Fabrication Department, fibergla

ss panels are attached to a canoe- shaped aluminum frame. The canoes are then transferred to the Waterproofing department to be coated with sealant. Arona uses a weighted-average process cost system to collect costs in both departments. All materials in the Fabrication Department are added at the beginning of the production process. On July 1, the Fabrication Department had 30 canoes in process that were 20% complete with respect to conversion cost. On July 31, Fabrication had 20 canoes in process that were 40% complete with respect to conversion cost. During July, the Fabrication Department completed 70 canoes and transferred them to the Waterproofing Department. What journal entry should Arona make to record the completion of the production process by the Waterproofing Department?
Business
1 answer:
nata0808 [166]3 years ago
5 0

Answer:

Arona Corporation

Journal Entry:

Debit Finished Goods Inventory $

Credit Work in Process - Waterproofing Department $

To transfer 70 canoes to the finished goods inventory.

Explanation:

Arona Corporation makes this entry to transfer 70 canoes to the finished goods inventory account in order to record the completion of the production process by the Waterproofing Department.  The Work in Process of the Waterproofing Department is credited with the value of 70 canoes multiplied by their unit costs.  Then the Finished Goods Inventory is debited to record the transfer.  These entries show that the Waterproofing Department is not indebted to the organization having completed its assignment.

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Answer:

Note: While answering this question, there is a confusion as to whether the correct demand equation is p= 157 − x2 as it appears in the question, or p= 157 − x^2 which is suspected to be the correct equation. Whichever the case may be, answers are provided for the two equations. Just confirm from the original question or your teacher which one is correct and pick the relevant answer out of the two following answers:

1. If p= 157 − x2 is the correct equation:

Elasticity of demand = - 0.15

Since -0.15 in absolute term |-0.15| is less than 1, the demand is inelastic.

2. If p= 157 − x^2 is the correct equation:

Elasticity of demand = - 0.28

Since -0.28 in absolute term |-0.28| is less than 1, the demand is also inelastic.

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Elasticity of demand is the degree of responsive of quantity demanded of a good to change in its price.

For this question, elasticity of demand can be computed using the formula for calculating the elasticity of demand as follows:

1. If p= 157 − x2 is the correct equation

E = Elasticity of demand = (p / x) * (dx / dp) ............................... (1)

From the question, we have:

p = 157 − x2.

Therefore, we solve for as follows:

x2 = 157 - p

x = (157 - P) / 2

x = 78.5 - 0.5p ....................................................... (2)

Differentiating equation (2) with respect to p, we have:

dx/dp = -0.5

Substituting values for dx/dp and x into equation (1), we have:

E = [p / (78.5 - 0.5p)] * (-0.5)

Since p = 20, we have:

E = [20 / (78.5 - (0.5 * 20))] * (-0.5)

E = [20 / (78.5 - 10)] * (-0.5)

E = − 0.15

Since -0.15 in absolute term |-0.15| is less than 1, the demand is inelastic.

2. If p = 157 − x^2 is the correct equation

E = (p / x) * (dx / dp) ............................................ (1)

From the question, we have:

p = 157 − x^2.

Therefore, we solve for as follows:

x = 157^(1/2) – p^(1/2)

x = 157^0.5 – p^0.5 ........................................... (2)

Differentiating equation (2) with respect to p, we have:

dx/dp = -0.5p^(-0.5) = -0.5/p^0.5

Substituting values for dx/dp and x into equation (1), we have:

E = (p / x) * (dx / dp)

E = [p /  (157^0.5 – p^0.5)] * [ -0.5/p^0.5]

Since p = 20, we have:

E = [20 /  (157^0.5 – 20^0.5)] * [–0.5/20^0.5]

E = - 0.28

Since -0.28 in absolute term |-0.28| is less than 1, the demand is inelastic.

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