So basically what you have to do is
The answer is a+6b, if you want to know the proof please comment on this post
Answer:
slope=10, y-int=-20. x-int=2
Step-by-step explanation:
The equation y=10x-20 is in slope-intercept form, or y=mx+b with m being the slope and b being the y-int. In this scenarion, the m(the slope) is 10 and the b(the y-int) is -20. For the x-int, you have to find out what x is when y=0 and vice versa for the y-int. In this case, 0=10x-20 so x=2. Therefor the x-int is 2.
From the total pool of colored balls, one can choose 2 reds, 2 blacks, 3 whites, and 2 blues in

ways.
I'm assuming no ball of the same color is distinguishable from any other ball of the same color. So when I'm considering the possible arrangements, if I had lined up the ball as
red1 - black - red2 - ...
then this would be no different that
red2 - black - red1 - ...
So I now have 9 balls to arrange, which means there are

total possible permutations of them. But order among distinct colors is assumed to not matter. This means I have to divide the total number of permutations by the number of ways I could permute balls of the same color. Then there would be a total of

ways of arranging the balls I had selected.
B. 12/24 is not equivalent because that is equal to 1/2 and 1/2 does not equal 8/20