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3 years ago

8

Chris answered 61 out of 66 questions correctly on a test. What is his test average to the nearest thousandth

1 answer:

mars1129 [50]3 years ago

4 0

If you divide 61 by 66, you will get .9242424. The thousandths place is the third number, so you base it off of the four number. If the fourth number is under 5, the third number stays the same and all numbers after it disappear. If the number is above 5, the third number rounds up 1 and the rest disappear. Because the 3rd number is 4 and the 4th number is 2, you will get the answer of .924

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katrin [286]

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3 years ago

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3 years ago

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Andrei [34K]

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Step-by-step explanation:

3 0

3 years ago

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Mae Ling earns a weekly salary of $325 plus a 7.5% commission

max2010maxim [7]

Answer:

$760

Step-by-step explanation:

Given data

weekly = $325

commission= 7.5%

if she sold $5,800 worth of merchandise

Her earnings will be

Week earning= base salary+ 7.5% of sales

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7 0

3 years ago

Given: ΔABC ≅ ΔEDF

V125BC [204]

we know that

the triangle ABC and triangle EDF are congruent triangles-----> given problem

therefore

$AC=EF\\AB=ED\\BC=DF$

we know that

the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(0,1)\\B(0,2)$

substitute in the formula of the distance

$d=\sqrt{(2-1)^{2}+(0-0)^{2}}$

$d=\sqrt{(1)^{2}+(0)^{2}}$

$dAB=1\ unit$

Step $2$

<u>Find the distance BC</u>

$B(0,2)\\C(3,2)$

substitute in the formula of the distance

$d=\sqrt{(2-2)^{2}+(3-0)^{2}}$

$d=\sqrt{(0)^{2}+(3)^{2}}$

$dBC=3\ units$

Step $3$

<u>Find the distance AC</u>

we know that

the triangle ABC is a right triangle

so

Applying the Pythagorean Theorem

$AC^{2}=AB^{2} +BC^{2}$

substitute the values in the formula

$AC^{2}=1^{2} +3^{2}$

$AC=\sqrt{10}\ units=3.16\ units$

round to the nearest tenth

$AC=3.2\ units$

therefore

$EF=3.2\ units$

$ED=1\ unit$

$DF=3\ units$

<u>the answer is</u>

The length of the hypotenuse is equal to $3.2\ units$

4 0

3 years ago

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