Answer:
3) 1 5/6 mi
4) a. 4 cm, 6 ft
b. 6.4 cm, 9.6 ft
c. same as part a
Step-by-step explanation:
3) Each of the given distances appears twice in the sum of side measures that is the perimeter. Hence by walking the perimeter twice, Kyle walks each of the given distances 4 times. His total walk is ...
4×1/3 + 4×1/8 = 4/3 + 4/8
= 1 1/3 + 1/2 = 1 2/6 + 3/6
= 1 5/6 . . . . . miles
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4) Since the figure is rectilinear (all angles are right angles, and all sides are straight lines), the sum of partial dimensions in one direction is equal to the whole dimension in that direction.
a. 8 cm = 4 cm + x
8 cm - 4 cm = x = 4 cm
The distance in the room is ...
(4 cm)×(1.5 ft/cm) = 6 ft
b. 10.3 cm = 3.9 cm + y
10.3 cm - 3.9 cm = y = 6.4 cm
The distance in the room is ...
(6.4 cm)×(1.5 ft/cm) = 9.6 ft
c. The answer to part b was obtained in the same way as the answer to part a. The unknown dimension is the difference of given dimensions. The actual length in the room is the model length multiplied by the inverse of the scale factor.
Yes and thank you for the points
Answer:
We accept the alternate hypothesis. We conclude that the mean lifetime of tires is is less than 33,000 miles.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 33,000 miles
Sample mean, 
= 32, 450 miles
Sample size, n = 18
Alpha, α = 0.05
Sample standard deviation, s = 1200 miles
a) First, we design the null and the alternate hypothesis
b) Level of significance:
c) We use One-tailed t test to perform this hypothesis.
d) Formula:
Putting all the values, we have
Now, 
Rejection area:
Since,
e) We fail to accept the null hypothesis and reject it as the calculated value of t lies in the rejection area.
f) We accept the alternate hypothesis. We conclude that the mean lifetime of tires is is less than 33,000 miles.
Answer:
1.3 million
Step-by-step explanation:
