The G.C.F of the given algebraic expression is; ⁴⁹/₆a xy
<h3>What is the G.C.F (Greatest Common Factor)?</h3>
The greatest common factor (GCF or GCD or HCF) of a set of whole numbers is the largest positive integer that divides evenly into all numbers with zero remainder. For example, for the set of numbers 18, 30 and 42 the GCF = 6.
We are given the algebraic expression;
(3 x y * 4x²y * ¹/₁ * 5x³y ^ z * 4)7a * 1/1 * 7*6
Expanding this further gives;
⁴⁹/₆a((3xy * 4x²y * 20x³y ^ z )
Now, the GCF of the terms inside the bracket would be x y. Thus, expanding the GCF we have;
⁴⁹/₆a xy((3 * 4x * 20x²y^(z - 1))
Read more about G.C.F at; brainly.com/question/219464
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I'm assuming it's 10^6, so 10 would be the base, and 6 would be the exponent.
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C(x)=- 0.3x^2+600x
y=ax^2+bx+c
it shows a upside down parabola equation.
to find maximum value we need to find its vertex(h,k)
as this is a standard quadratic equation we need to see parabolis equation too
y=a(x-h)^2+k
if u see this eq^n K would be the maximum value of Y if x=h.
where h,k are vertex of parabola.
h=-b/2a(derived standard formula)
C(x)=- 0.3x^2+600x
y=ax^2+bx+c
a= -0.3 b=600
h=-600/-0.3
h= 2000
put h in place of x to get K
K= -0.3(2000)^2+600(2000)
K= - 1200000+1200000
K=0
u gets k=0
means C(x)=0
600x= -0.3x^2
600= 0.3x
x=6000/3
x= 2000 units
