THIS IS DUE IN 5 MINUTES!!!!!!!!!!! I NEEED THIS ASAP! A 13 3/4 -inch candle burns down in 11 hours. If b represents how much of
2 answers:
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Hey there!
This seems like a algebraic expression
SO,
Remember: negative and negative = positive
positive and positive = positive
positive and negative = negative
negative and positive = negative
In this problem we will be doing negative and negative so that means our answer will be a negative
Firstly, lets line up our decimals to solve this problem (once when you do that , you can solve it easier)
Answer:
Good luck on your assignment and enjoy your day
~
This seems like a algebraic expression
SO,
Remember: negative and negative = positive
positive and positive = positive
positive and negative = negative
negative and positive = negative
In this problem we will be doing negative and negative so that means our answer will be a negative
Firstly, lets line up our decimals to solve this problem (once when you do that , you can solve it easier)
Answer:
Good luck on your assignment and enjoy your day
~
Answer:
x = 2
Step-by-step explanation:
These equations are solved easily using a graphing calculator. The attachment shows the one solution is x=2.
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<h3>Squaring</h3>The usual way to solve these algebraically is to isolate radicals and square the equation until the radicals go away. Then solve the resulting polynomial. Here, that results in a quadratic with two solutions. One of those is extraneous, as is often the case when this solution method is used.
The solutions to this equation are the values of x that make the factors zero: x=2 and x=-1. When we check these in the original equation, we find that x=-1 does not work. It is an extraneous solution.
x = -1: √(-1+2) +1 = √(3(-1)+3) ⇒ 1+1 = 0 . . . . not true
x = 2: √(2+2) +1 = √(3(2) +3) ⇒ 2 +1 = 3 . . . . true . . . x = 2 is the solution
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<h3>Substitution</h3>Another way to solve this is using substitution for one of the radicals. We choose ...
Solutions to this equation are ...
u = 2, u = -1 . . . . . . the above restriction on u mean u=-1 is not a solution
The value of x is ...
x = u² -2 = 2² -2
x = 2 . . . . the solution to the equation
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<em>Additional comment</em>
Using substitution may be a little more work, as you have to solve for x in terms of the substituted variable. It still requires two squarings: one to find the value of x in terms of u, and another to eliminate the remaining radical. The advantage seems to be that the extraneous solution is made more obvious by the restriction on the value of u.
