Find four consecutive integers such that the sum of the two largest subtracted from three times the sum of the two smallest is 7

Mathematics

1 answer:

serious [3.7K]3 years ago

7 0

Answer:

18, 19, 20, 21

Step-by-step explanation:

Just like any of these problems, we should start by forming an equation for us to get a reference and plug in. We'll be using x as our variables.

As we have four consecutive integers (and not multiples) we can assume that the integers will be x, x+1, x+2, and x+3.

The sum of the two largest integers we have equals: n+2 + n+3 = 2n+5

and three times the sum of the two smallest = 3(n + n+1) = 6n+3

and the sum of t he two largest subtracted from three times the sum of the two smallest = (6n+3) - (2n+5) = 4n-2

4n-2=70

4n=68

n = 18.

n = 18, n+1 = 19, n+2 = 20, n+3 = 21

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Find the missing side 13 ft 5 ft x

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Answer:

Assuming you're referring to the sides of a right triangle, the missing side X would be 12.

Step-by-step explanation:

The Pythagorean Theorem states that the two legs of a right triangle squared and added together is equal to the hypotenuse squared. $13^{2}$ is 169, $5^{2}$ is 25, 169 - 25 = 144. Take the square root of 144 and you'll get 12, which is the missing side of the right triangle.