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natita [175]
3 years ago
9

I need answers plz guys help me now ​

Mathematics
1 answer:
Serjik [45]3 years ago
6 0

Answer:

Equation : y=3x

Interpret the slope : 3

Interpret the y-Intercept : 0

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Find f(–2) for the function f(x) = 3x2 – 2x + 7.
Natasha_Volkova [10]

The correct answer is: 23

Explanation:

Given function:

f(x) = 3x^2 - 2x + 7 ---- (A)

f(-2) means that we have to put x = -2 in equation (A):

f(-2) = 3(-2)^2 - 2(-2) + 7 \\ f(-2) = 3*4 + 4 + 7 \\ f(-2) = 12+4+7 \\ f(-2) = 23 \\


Hence the correct answer is: f(-2) = 23.

8 0
3 years ago
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PLEASE HELP-
oksano4ka [1.4K]

Answer:

-3,2(that is the right answer

4 0
3 years ago
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Which is the best estimate for the mass of a desktop computer
allsm [11]
A is the answer 500g
4 0
3 years ago
Factorise x^2+6x-7 ?? Help please
Ber [7]
x^2+6x-7=\\
x^2-x+7x-7=\\
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(x+7)(x-1)
7 0
3 years ago
Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. ​(a) Descr
Daniel [21]

Answer:

(a) The sampling distribution of\overline{X} = Population mean = 79

(b)  P ( \overline{X} greater than 81.2 ) =  0.1357

(c) P (\overline{X} less than or equals 74.4 ) = .0107

(d) P (77.6 less than \overline{X} less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean (\nu) = 79

Standard deviation (\sigma ) = 18

​(a) Describe the sampling distribution of \overline{X}

For large sample using central limit theorem

the sampling distribution of\overline{X} = Population mean = 79

​(b) What is Upper P ( \overline{X} greater than 81.2 )​ =

P(\overline{X}> 81.2)  = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})

                    =  P(Z> 1.1)

                    = 1 - P(Z<   1.1)

                    = 1 - .8643 =

                    = 0.1357

(c) What is Upper P (\overline{X} less than or equals 74.4 ) =

P(\overline{X}\leq  74.4) = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq  \frac{74.4- 79}{\frac{18}{\sqrt{81}}})

                    = P(Z\leq  -2.3)

                    = .0107

​(d) What is Upper P (77.6 less than \overline{X} less than 83.2 ) =

P(77.6< \overline{X}<   83.2) = P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq  \frac{83.2- 79}{\frac{18}{\sqrt{81}}})

                                = P(- 0.7< Z<   2.1)

                                 = (Z<   2.1) - (Z<   -0.7)

                                  = 0.9821 - .2420

                                   = 0.7401

3 0
3 years ago
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