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tino4ka555 [31]
2 years ago
8

50 points! Find the coordinates of the centroid of the triangle with the vertices A(-6,8), B(-3,1),andC(0,3). Random answers wil

l be reported guys
Mathematics
2 answers:
Lerok [7]2 years ago
4 0

Answer:

the coordinates of the centroid of the triangle with the vertices A(-6,8), B(-3,1),andC(0,3).

={(-6-3-0)/3,(8+1+3)/3}=(-<em>3</em><em>,</em><em>4</em><em>)</em>

Vladimir [108]2 years ago
4 0

Answer:

<em>( - 3, 4 )  </em>

Step-by-step explanation:

The centroid of a triangle is the intersection of the three medians of the triangle.

A ( - 6, 8 )

C ( 0, 3 )

Coordinates of the midpoint of AC are D( - 3, 5.5 )

Median BD is x = - 3

Coordinates of midpoint of BC are E( - 1.5, 2 )

m_{AE} = - \frac{4}{3}

Equation of median AE is y = - \frac{4}{3} x

Solve system of equations:

y = - \frac{4}{3} x and x = - 3

<em>( - 3, 4 ) are coordinates of the centroid of the Δ ABC </em>

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Find the surface area of the ball shown to the right <br><br> d=20
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<h3>Surface Area = 1,256 cm</h3>

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You have been saving $12 each week for many weeks. One day, you decide to count your savings and find that you have $384. Write
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Hope I helped! Brainleist!

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5 0
3 years ago
Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt
-Dominant- [34]

Using the t-distribution, it is found that since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

At the null hypothesis, it is <u>tested if it does not outlast by more than 2 hours</u>, that is, the subtraction is not more than 2:

H_0: \mu_B - mu_A \leq 2

At the alternative hypothesis, it is <u>tested if it outlasts by more than 2 hours</u>, that is:

H_1: \mu_B - \mu_A > 2

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Hence, the standard errors are:

s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934

The distribution of the difference has <u>mean and standard deviation</u> given by:

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The test statistic is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 2 is the value tested at the hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{2.58 - 2}{0.2735}

t = 2.12

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Since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

7 0
3 years ago
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