This involves basic arithmetic calculations and simultaneous equations.
Adamu has 25 Cards
Let the following letters represent the number of cards each has;
A: ADAMU
F: FUNKE
S: SHEHU
K: KWAME
T: TANKO
- If adamu gives funke 5 cards, he will have as many as tanko. Thus;
A - 5 = T --- eq 1
- If funke gives adamu 4 cards, he will have as many as kwame. Thus;
A + 4 = K --- eq 2
- Funke and adamu have a total of 13 more cards than the total that kwame and tanko have. Thus;
A + F = K + T + 13 --- eq 3
- Adamu has 2 cards more than what Shehu has. Thus;
A - 2 = S --- eq 4
From online research, the Total Number of cards is 134 and not 133. Thus;
A + F + K + S + T = 134 --- eq 5
Let's put A - 5 = T and A + 4 = K in eq 3 to get;
A + F = (A + 4) + (A - 5) + 13
A + F = 2A + 12
F = 2A - A + 12
F = A + 12
Let's put A - 2 = S ; F = A + 12 ; A - 5 = T and A + 4 = K into eq 5 to get;
A + A + 12 + A + 4 + A - 2 + A - 5 = 134
Simplifying gives;
5A + 9 = 134
5A = 134 - 9
5A = 125
A = 125/5
A = 25
Adamu has 25 Cards
Answer:
10, he should round the quotient up by 1 because of the remainder
Step-by-step explanation:
Brandon did all of the math work correctly, but you can't over crowd the bus with 13 people. The 10th bus will not be filled to capacity but it would be enough for the 4 remaining fourth graders.
9x^8
lmk if this helped :)
Answer:
∠DCF = 129°
Step-by-step explanation:
We assume that line CE is between lines CD and CF.
The angle sum theorem applies:
∠DCF = ∠DCE +∠ECF
∠DCF = 75° +54°
∠DCF = 129°
Answer:
28, 56, 84, 112, etc.
Step-by-step explanation:
Since 28 is the first number they have in common, 28 is the least common multiple of 4 and 7.
