For the first one, you did good. I will just suggest a couple things.
Statement Reason
JK ≅ LM Given
<JKM ≅ < LMK Given (You did both of these steps so well done.)
MK ≅ MK Reflexive Property (Your angle pair is congruent but isn't one of the interior angle of the triangles you are trying to prove.)
ΔJMK ≅ ΔLKM SAS
Problem 2: (You also have a lot of great stuff here.)
Statement Reason
DE ║ FG Given
DE ≅ FG Given
<DEF≅<FGH Given
<EDF≅<GFH Corresponding Angles (You don't need to know that F is the midpoint but you got corresponding angle pair which is correct.)
ΔEDF≅ΔGFH ASA
<DFE≅<FHG CPCTC
Graph images undergo transformations, one of the types of transformations are rotations.
rotation is done when each point of the image rotates 90° around a point in the counterclockwise manner.
when rotation is done, (x,y) -> (-y,x)
therefore when taking points from image to original then the reverse is done ;
(-y,x) --> (x,y)
the coordinates of image point q' is (-3,4)
before rotation then the coordinates are (4,3)
answer is (4,3)
Answer:
y + 1 = 3(x - 1)
Step-by-step explanation:
The given point is (1,-1) meaning that x1 = 1 and y1 = -1
The slope of this line is m = 3 because we go up 3 and over to the right 1 (eg: go from the point (1,-1) to (2,2) to see this in action)
Plug these three pieces of info into the point slope formula below
y - y1 = m(x - x1)
y - (-1) = 3(x - 1)
y + 1 = 3(x - 1)
Answer:
The hypotenuse to the nearest tenth is 8.1
Step-by-step explanation:
We can use the Pythagorean theorem to solve
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
Let a be the x leg and b be the y leg
a = 7 units
b= 4 units
7^2 + 4^2 = c^2
49+ 16 = c^2
65 = c^2
Take the square root of each side
sqrt(65) = sqrt(c^2)
8.062257748 =c
To the nearest tenth
8.1 =c
Answer:
Step-by-step explanation:
2) Take the number you see (7). How many 7s are there? There are three.
7 x 3
3) What number do you see? 3. How many 3s? Five 3s.
3 x 5
Now you try
