Question

write the equation of a line in any form that is parallel 2y = 4x + 8 through the point of (1,3) plz and thank you

Answer 1

Step-by-step explanation:

Hey, there!!

Here, the given point is (1,3).

Now, Using one point formula we need to find the equation of the line passing through point (1,3).

Now,

$(y - y1) = m1(x - x1)$

Keeping values,

$(y - 3) = m1(x - 1)$

It is the 1st equation.

Similary, you have another equation,

2y = 4x + 8..............2nd equation.

or, 4x - 2y +8 =0

M2 from equation 2,

$= \frac{ - coeff. \: of \: x}{coeff. \: of \: y}$

$= \frac{ - 4}{ - 2}$

Therefore, m2 = 2

Now,

As per the condition of parallel lines,

m1 = m2 = 2

Now, substituting the value of m1 in equation 1st.

(y-3) = 2 (x-1)

y-3 = 2x - 2

or, 2x-y+1 = 0 ......is the required equation.

Hope it helps...

Answer 2

Answer:

y = 2x+1

Step-by-step explanation:

$2y =4x+8\\\\ Write \:in \: y =mx+b \:form\\\\\frac{2y}{2} = \frac{4x}{2} +\frac{8}{2} \\\\y =2x +4\\m =2\\(1,3) =(x_1,y_1)\\Substitute\:values\:into\:point-slope\:form\\\\y-y_1=m(x-x_1)\\y-3=2(x-1)\\y-3 = 2x-2\\y=2x-2+3\\y =2x+1$