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weqwewe [10]
2 years ago
5

write the equation of a line in any form that is parallel 2y = 4x + 8 through the point of (1,3) plz and thank you

Mathematics
2 answers:
amid [387]2 years ago
6 0

Step-by-step explanation:

Hey, there!!

Here, the given point is (1,3).

Now, Using one point formula we need to find the equation of the line passing through point (1,3).

Now,

(y - y1) = m1(x - x1)

Keeping values,

(y - 3) = m1(x - 1)

It is the 1st equation.

Similary, you have another equation,

2y = 4x + 8..............2nd equation.

or, 4x - 2y +8 =0

M2 from equation 2,

=  \frac{ - coeff. \: of \: x}{coeff. \: of \: y}

=   \frac{ - 4}{ - 2}

Therefore, m2 = 2

Now,

As per the condition of parallel lines,

m1 = m2 = 2

Now, substituting the value of m1 in equation 1st.

(y-3) = 2 (x-1)

y-3 = 2x - 2

or, 2x-y+1 = 0 ......is the required equation.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

V125BC [204]2 years ago
4 0

Answer:

y = 2x+1

Step-by-step explanation:

2y =4x+8\\\\ Write \:in \: y =mx+b \:form\\\\\frac{2y}{2} = \frac{4x}{2} +\frac{8}{2} \\\\y =2x +4\\m =2\\(1,3) =(x_1,y_1)\\Substitute\:values\:into\:point-slope\:form\\\\y-y_1=m(x-x_1)\\y-3=2(x-1)\\y-3 = 2x-2\\y=2x-2+3\\y =2x+1

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(- 19, - 11, 5, 25)

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The given function is f(x) = 4x - 7

Now, we have to find the range of the given function for the given domains.

The domains are given as (2 - 5, - 1, 3, 8) i.e. (- 3, - 1, 3, 8).

Therefore, f(- 3) = 4(- 3) - 7 = - 19

f(- 1) = 4(- 1) - 7 = - 11

f(3) = 4(3) - 7 = 5

f(8) = 4(8) - 7 = 25

So, the ranges of the function are (- 19, - 11, 5, 25) (Answer)

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Let X be the temperature in at which a certain chemical reaction takes place, and let Y be the temperature in (so Y = 1.8X + 32)
Black_prince [1.1K]

Answer:

See explanation

Step-by-step explanation:

Solution:-

The random variable, Y be the temperature of chemical reaction in degree fahrenheit be a linear expression of a random variable X : The  temperature in at which a certain chemical reaction takes place.

                             Y = 1.8*X + 32

- The median of the random variate "X" is given to be equal to "η". We can mathematically express it as:

                             P ( X ≤ η ) = 0.5

- Then the median of "Y" distribution can be expressed with the help of the relation given:

                             P ( Y ≤ 1.8*η + 32 )

- The left hand side of the inequality can be replaced by the linear relation:

                             P ( 1.8*X + 32 ≤ 1.8*η + 32 )

                             P ( 1.8*X ≤ 1.8*η )   ..... Cancel "1.8" on both sides.

                            P ( X ≤ η ) = 0.5 ...... Proven

Hence,

- Through conjecture we proved that: (1.8*η + 32) has to be the median of distribution "Y".

b)

- Recall that the definition of proportion (p) of distribution that lie within the 90th percentile. It can be mathematically expressed as the probability of random variate "X" at 90th percentile :

                             P ( X ≤ p_.9 ) = 0.9 ..... 90th percentile

- Now use the conjecture given as a linear expression random variate "Y",

          P ( Y ≤ 1.8*p_0.9 + 32 ) = P ( 1.8*X + 32 ≤ 1.8*p_0.9 + 32 )

                                                 = P ( 1.8*X ≤ 1.8*p_0.9 )

                                                 = P ( X  ≤ p_0.9 )

                                                 = 0.9

- So from conjecture we saw that the 90th percentile of "X" distribution is also the 90th percentile of "Y" distribution.

c)

- The more general relation between two random variate "Y" and "X" is given:

                            Y = aX + b

Where, a : is either a positive or negative constant.

- Denote, (np) as the 100th percentile of the X distribution, so the corresponding 100th percentile of the Y distribution would be : (a*np + b).

- When a is positive,

                   P ( Y ≤ a*p_% + b ) = P ( a*X + b ≤ a*p_% + b )

                                                 = P ( a*X ≤ a*p_% )

                                                 = P ( X  ≤ p_% )

                                                 = np_%        

- When a is negative,

                   P ( Y ≤ a*p_% + b ) = P ( a*X + b ≤ a*p_% + b )

                                                 = P ( a*X ≤ a*p_% )

                                                 = P ( X  ≥ p_% )

                                                 = 1 - np_%        

                                                           

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2 years ago
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