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LenaWriter [7]
2 years ago
12

lisa is riding on a bike course that is 80 miles long. Do far, she has ridden 52 miles if the course. What percentage of the cou

rse has lisa ridden so far
Mathematics
1 answer:
Otrada [13]2 years ago
7 0
She has gone 65% of the way on the bike course
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miss Akunina [59]

I think its 180/24 here is my work

\frac{3}{8}\\=\\ \\\frac{9}{24} \\\\\frac{5}{6}\\=\\ \\\frac{20}{24} \\ so you find the lcm of \frac{20}{24} and  \frac{9}{24} = 180/24

5 0
3 years ago
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Quick algebra 1 question for 50 points!
Naddika [18.5K]

The line is parallel to y axis

We know that if a line is parallel to y axis

  • slope=tan90=undefined

So there is no slope

Here it has constant x value as -2

So the equation is

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Option A

7 0
2 years ago
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The graph shows the function f(x)=3^x
tangare [24]
The answer is D.
You have to make the whole numbers equal to then solve for the exponents:
F(x) means y, therefore, y is 9.
9 = 3^x.
3^2 is the same as 9.
Then, 3^2 = 3^x.
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Therefore your answer is 2.
8 0
3 years ago
Match the following items by evaluating the expression for x = -7. x-2 x-1 x0 x1 x2
frosja888 [35]

Answer:

{x}^{ - 2}  =  \frac{1}{ {x}^{2} }  \:  \: –> {7}^{ - 2}  =  \frac{1}{ {7}^{2} }  =  \frac{ 1}{49}  \\  \\  {x}^{ - 1}  =  \frac{1}{ {x}^{1} }   \: –>  {7}^{ - 1}  =  \frac{1}{ {7}^{1} } =  \frac{1}{7}  \\  \\  {x}^{0} –> {7}^{0}   = 1 \\  \\  {x}^{1}  –> {7}^{1}  = 7 \\  \\  {x}^{2}  –> {7}^{2}  = 49

7 0
2 years ago
Please Help I will give you a lot of points if you do!
Maru [420]

Answer:

De Morgan's Theorem, T12, is a particularly powerful tool in digital design. The theorem explains that the complement of the product of all the terms is equal to the sum of the complement of each term. Likewise, the complement of the sum of all the terms is equal to the product of the complement of each term.

Step-by-step explanation:

De Morgan's Theorem, T12, is a particularly powerful tool in digital design. The theorem explains that the complement of the product of all the terms is equal to the sum of the complement of each term. Likewise, the complement of the sum of all the terms is equal to the product of the complement of each term.

4 0
2 years ago
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