Question

The sum of 2 consecutive integers is 21 what’s the two numbers

Answer 1

Answer:

10 and 11

Step-by-step explanation:

Let the first integer be x.

Then the next one, since it's consecutive, must be (x+1).

The two equals 21. Thus:

$(x)+(x+1)=21$

Combine like terms:

$2x+1=21$

Subtract 1 from both sides:

$2x=20$

Divide both sides by 2:

$x=10$

So, the first integer is 10.

And the second integer is 10+1=11.

Answer 2

Answer:

10 , 11

Step-by-step explanation:

The sum of two consecutive integers is 21.

Let the least of the integer be signified by the variable x.

Consecutive means "directly after", which means the other integer would be: x + 1

Set the equation:

(x) + (x + 1) = 21

Simplify. Combine like terms:

x + x + 1 = 21

(x + x) + 1 = 21

2x + 1 = 21

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 1 from both sides:

2x + 1 (-1) = 21 (-1)

2x = 21 - 1

2x = 20

Next, divide 2 from both sides:

(2x)/2 = (20)/2

x = 20/2

x = 10

Plug in 10 for x in the equation:

(x) + (x + 1) = 21

10 + (10 + 1) = 21

10 + 11 = 21

21 = 21 (True)

The two numbers are 10, 11.

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