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V125BC [204]
3 years ago
13

A shelter has enough food to feed an average of 80 hungry people a day for 14 days. If an average of 32 people are at the shelte

r each day, how long will the food last?
Mathematics
2 answers:
Katen [24]3 years ago
6 0

Answer:

  • <u>35 days. </u>

Explanation

The capacity of the shelter is a constant. It is 80 people × 14 days.

That is an inverse relation: the product of the number of people and the number of days will be always the same.

As the number of people decreases the number of days that the food lasts increases, in a proportion such that the product of the days and the number of people is the same.

Thus, for 32 people the number of days the food lasts is x, such that:

  • 32 people × x = 80 people × 14 days

Solving for x:

  • x = 80 people × 14 days / 32 people
  • x = 35 days ← answer

The food will last 35 days.

spin [16.1K]3 years ago
3 0

Answer: 35 days


Step-by-step explanation:

Given: A shelter has enough food to feed an average of 80 hungry people a day for 14 days.

Let y be the number of days if  32 people are at the shelter .

The number of hungry people and number of days are in inverse proportion

Therefore, 80\times14=32\times\ x\\\Rightarrow\ x=\frac{80\times14}{32}\\\Rightarrow\ x=35

Therefore, if an average of 32 people are at the shelter each day, the food will last for 35 days.

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Simora [160]

Answer:

Austin will have to buy 180 squares of carpeting.

Step-by-step explanation:

First find the dimension of the room. We do that by multiplying the width times the length and then subtracting the cut out region in the top right. And, in order to know how big that region we cut out is, we have to do a little subtraction.

We know the room is 18' long on the left side and 12' long on the right side. We subtract 12 from 18 to get 6, and we know that the cut out region is 6' long. We do the same thing with the width, 25' wide at the bottom minus 10' wide at the top and we see that the cut out is 15' wide.

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5 0
3 years ago
Men are believed to have a slightly longer average length of short hospital stays than women; 5.2 days versus 4.5 days respectiv
Georgia [21]

Answer:

Since our calculated value is lower than our critical value,z_{calc}=2.02, we have enough evidence to FAIL to reject the null hypothesis at 1% of singificance. So there is not nough evidence to conclude that mean for men it's significantly higher than the mean for female.

Step-by-step explanation:

1) Data given and notation  

\bar X_{1}=5.2 represent the mean for group men  

\bar X_{2}=4.5 represent the mean for group women  

Assuming these values for the remaining data:

\sigma_{1}=1.2 represent the population standard deviation for the sample men

\sigma_{2}=1.5 represent the population standard deviation for the sample women

n_{1}=32 sample size for the group men  

n_{2}=30 sample size for the group women  

z would represent the statistic (variable of interest)

p_v represent the p value  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for men it's higher than the mean for women, the system of hypothesis would be:  

H0:\mu_{1} \leq \mu_{2}  

H1:\mu_{1} > \mu_{2}  

If we analyze the size for the samples both are higher than 30, and we know the population deviation's, so for this case is better apply a z test to compare means, and the statistic is given by:  

z=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

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We have all in order to replace in formula (1) like this:  

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"=NORM.INV(1-0.01,0,1)", and we got z_{critical}=2.33

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Since our calculated value is lower than our critical value,z_{calc}=2.02, we have enough evidence to FAIL to reject the null hypothesis at 1% of significance. So there is not nough evidence to conclude that mean for men it's significantly higher than the mean for female.

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</span>
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