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anyanavicka [17]

2 years ago

9

A bag holds 5 pounds of pet food. If Paul uses the 5 pounds of food to fill 6 plastic containers equally how much pet food will

each container hold

1 answer:

serg [7]2 years ago

5 0

Answer: 13 1/3 ounces

Explanation:
1 pound equals 16 ounces
5 x 16=80
80 ounces divided by 6 containers is equal to 13 1/3 ounces of pet food.

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4 0

2 years ago

Find the value of k such that lim-->4 (x^2+x-k)/(x-4) exists

7nadin3 [17]

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k=20

Step-by-step explanation:

when x approaches 4, the denominator x-4 approaches 0

if the denominator is 0, it means that this is invalid

if the function is a number over 0 when x=4, it represents a vertical asymptote, which means no limit

so the only way possible to let there be a limit is to let the function be 0/0 when we plug in x=4

so x^2 + x - k = 0 when x = 4

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6 0

2 years ago

Solve each system by elimination.

max2010maxim [7]

Answer:

Step-by-step explanation:

-x-2y+4z=-14

x=-2y+4z+14

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2x=-2y-2z-6

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3 years ago

In rectangle ABCD, point E lies half way between sides AB and CD and halfway between sides AD and BC. If AB=3 and BC=2, what is

Alex777 [14]

Answer:

<em>The area of the shaded region is 3.</em>

Step-by-step explanation:

Since point E lies halfway between AB and BC, the area of the shaded region (As) consists of two identical triangles with base equal to AB and height equal to half the measure of BC:

$A_s=2 * A_t$

Where At is the area of each triangle.

$\displaystyle A_t=\frac{AB*BC/2}{2}$

$\displaystyle A_t=\frac{AB*BC}{4}$

We know AB=3 and BC=2, thus:

$\displaystyle A_t=\frac{3*2}{4}=\frac{6}{4}$

Simplifying:

$\displaystyle A_t=\frac{3}{2}$

Finally:

$\displaystyle A_s=2 * \frac{3}{2}$

$A_s=3$

The area of the shaded region is 3.

Note the area of the shaded region is half the area of the rectangle.

3 0

2 years ago