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3 years ago

I need help with this problem and show your work plz thanks

Mathematics

1 answer:

coldgirl [10]3 years ago

5 0

Well is just their sum, thus

$\bf \cfrac{3}{4}+\cfrac{2}{3}\impliedby \stackrel{LCD~is}{12}\implies \cfrac{(3)3+(4)2}{12}\implies \cfrac{9+8}{12}\implies \cfrac{17}{12}\implies 1\frac{5}{12}$

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The volume of a right circular cone with radius r and height h is V = pir^2h/3.

Scorpion4ik [409]

The question is incomplete. The complete question is :

The volume of a right circular cone with radius r and height h is V = pir^2h/3. a. Approximate the change in the volume of the cone when the radius changes from r = 5.9 to r = 6.8 and the height changes from h = 4.00 to h = 3.96.

b. Approximate the change in the volume of the cone when the radius changes from r = 6.47 to r = 6.45 and the height changes from h = 10.0 to h = 9.92.

a. The approximate change in volume is dV = _______. (Type an integer or decimal rounded to two decimal places as needed.)

b. The approximate change in volume is dV = ___________ (Type an integer or decimal rounded to two decimal places as needed.)

Solution :

Given :

The volume of the right circular cone with a radius r and height h is

$V=\frac{1}{3} \pi r^2 h$

$dV = d\left(\frac{1}{3} \pi r^2 h\right)$

$dV = \frac{1}{3} \pi h \times d(r^2)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

a). The radius is changed from r = 5.9 to r = 6.8 and the height is changed from h = 4 to h = 3.96

So, r = 5.9 and dr = 6.8 - 5.9 = 0.9

h = 4 and dh = 3.96 - 4 = -0.04

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (5.9)(4)(0.9)+\frac{1}{3} \pi (5.9)^2 (-0.04)$

$dV=44.484951 - 1.458117$

$dV=43.03$

Therefore, the approximate change in volume is dV = 43.03 cubic units.

b). The radius is changed from r = 6.47 to r = 6.45 and the height is changed from h = 10 to h = 9.92

So, r = 6.47 and dr = 6.45 - 6.47 = -0.02

h = 10 and dh = 9.92 - 10 = -0.08

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (6.47)(10)(-0.02)+\frac{1}{3} \pi (6.47)^2 (-0.08)$

$dV=-2.710147-3.506930$

$dV= -6.22$

Hence, the approximate change in volume is dV = -6.22 cubic units

8 0

2 years ago

Aida makes $9.25 per hour. Aida works 14 hours in one week. At the end of the week, Aida deposits 1/5 of her total income into a

Lina20 [59]

Answer:

$103.6 left

Step-by-step explanation:

First, multiply the amount she earns an hour times how many hours she worked:

9.25 x 14 = 129.5

Then divide the total by 1/5:

129.5 / 5 = 25.9

Then subtract that value from the total:

129.5 - 25.9 = 103.6

$103.6 is your answer

Hope this helps!

4 0

2 years ago

Read 2 more answers

If the measure of ABC is 68, what is the measure of AB?

NARA [144]

Answer: 136 is your answer

Step-by-step explanation:

4 0

3 years ago

Why is 3 + (-5) equal to -2

Ilia_Sergeevich [38]

When you add a positive and a negative like you did here it basically is the same as subtracting 5 from 3

6 0

3 years ago

Read 2 more answers

!!30 POINTS!!

lana66690 [7]

For this case we have the following functions:
f (x) = 3x + 4
g (x) = 2 ^ x - 1
The intersection with the y axis of the original functions is:
f (0) = 3 (0) + 4 = 0 + 4 = 4
g (0) = 2 ^ 0 - 1 = 1 - 1 = 0
The transformations that must be applied so that they have the same intersection with the y axis are:
f (x) - 3
g (x) + 1
Answer:
f (x) - 3
g (x) + 1
option 1

8 0

2 years ago