I need help with this problem and show your work plz thanks

Mathematics

1 answer:

coldgirl [10]3 years ago

5 0

Well is just their sum, thus

$\bf \cfrac{3}{4}+\cfrac{2}{3}\impliedby \stackrel{LCD~is}{12}\implies \cfrac{(3)3+(4)2}{12}\implies \cfrac{9+8}{12}\implies \cfrac{17}{12}\implies 1\frac{5}{12}$

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Bella has 6.3 kg of berries. she packs 0.35 kg of berries in each containers. then sells each container for $2.99. how much mone

katovenus [111]

Answer:

$53.82

Step-by-step explanation:

6.3 / 0.35=18

$2.99 x 18= $53.82

hope this halps :)

8 0

3 years ago

Solve the inequality for x 3^(6x+18)<27^(3x)

Lera25 [3.4K]

Answer:

$\displaystyle x > 6$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Factoring

Algebra II

Exponential Rule [Powering]: $\displaystyle (b^m)^n = b^{m \cdot n}$
Solving exponential equations

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle 3^{6x + 18} < 27^{3x}$

Step 2: Solve for x

Rewrite: $\displaystyle 3^{6x + 18} < 3^{3(3x)}$
Set: $\displaystyle 6x + 18 < 3(3x)$
Factor: $\displaystyle 3(2x + 6) < 3(3x)$
[Division Property of Equality] Divide 3 on both sides: $\displaystyle 2x + 6 < 3x$
[Subtraction Property of Equality] Subtract 3x on both sides: $\displaystyle -x + 6 < 0$
[Subtraction Property of Equality] Subtract 6 on both sides: $\displaystyle -x < -6$
[Division Property of Equality] Divide -1 on both sides: $\displaystyle x > 6$