Answer:1866
Step-by-step explanation:
Given
n=200
x=118
Population proportion P=
=0.59
=0.005
Realiability =99%
Margin of erroe is given by 
0.03= 
85.667=![\sqrt{\frac{N}{0.6519}}[tex]N=1865.88[tex]\approx 1866 Students](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7BN%7D%7B0.6519%7D%7D%5Btex%5D%3C%2Fp%3E%3Cp%3EN%3D1865.88%5Btex%5D%5Capprox%201866%20Students)
Answer = 5 problems per minute
Because you do the number of problems divided by the minutes eg 35/7 = 5
16.76 rounds off to 17
After the dot if it’s 1-4 then they it would’ve been 15
5-9 is 17
Answer:
Step-by-step explanation:
1. Null hypothesis: u <= 0.784
Alternative hypothesis: u > 0.784
2. Find the test statistics: z using the one sample proportion test. First we have to find the standard deviation
Using the formula
sd = √[{P (1-P)}/n]
Where P = 0.84 and n = 750
sd =√[{0.84( 1- 0.84)/750]}
sd=√(0.84 (0.16) /750)
SD =√(0.1344/750)
sd = √0.0001792
sd = 0.013
Then using this we can find z
z = (p - P) / sd
z = (0.84-0.784) / 0.013
z =(0.056/0.013)
z = 4.3077
3. Find the p value and use it to make conclusions...
The p value at 0.02 level of significance for a one tailed test with 4.3077 as z score and using a p value calculator is 0.000008254.
4. Conclusions: the results is significant at 0.02 level of significance suck that we can conclude that its on-time arrival rate is now higher than 78.4%.
Answer: See explanation
Step-by-step explanation:
Your question isn't complete. But let's assume that the amount earned on Monday is $38 while $25 was earned on Tuesday.
The total amount earned for both days will be:
= $38 + $25
= $63
Since lucky bamboo plants are $7 each, we then divide the total amount gotten by $7. This will be:
= $63 / $7
= 9
Therefore, he can buy 9 lucky bamboos
