All categories

3 years ago

Josiah has a loyalty card good for a discount at his local grocery store. The item he

Mathematics

2 answers:

Juli2301 [7.4K]3 years ago

4 0

(18.27/21)x100=87
100-87=13% discount

Rina8888 [55]3 years ago

3 0

Answer:

13%

Step-by-step explanation:

You might be interested in

What is .235 written as a fraction?

Keith_Richards [23]

0.235 = 235/1000= 47/200

Answer: 47/200

*Hope that helps and enjoy Brainly :)*

5 0

3 years ago

Read 2 more answers

_____ are birds which are famous for performing a ritualized mating dance.

padilas [110]

I do believe it’s D. Albatrosses

7 0

3 years ago

Read 2 more answers

How to factorise 3x2-12x+3

Fofino [41]

Factor 3x^2 - 12x + 3

3x^2 - 12x + 3

answer is 3(x^2 - 4x + 1)

3 0

3 years ago

A test has 40 questions. Denise finished 2\5 of the questions in the first 10 minutes and 1\2 of the total questions in the next

leonid [27]

Answer:

28 questions answered.

Step-by-step explanation:

40(2/5) is 16 questions.

40-16 is 24 questions left.

24(.5) is 12 questions.

16+12 gets you 28 questions.

8 0

3 years ago

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

3 years ago