Question

Which option is correct and how would one solve for it?

Answer 1

Answer:

102

Step-by-step explanation:

We have the sum for k = 1 to 4 of 3 ^ ( k-1)  * ( k-1)

k =1   3 ^ (1-1) * ( 1-1) = 3^0 * 0 = 0

k =2   3 ^ (2-1) * ( 2-1) = 3^1 * 1 = 3

k =3   3 ^ (3-1) * ( 3-1) = 3^2 * 2 = 9*2 = 18

k =4   3 ^ (4-1) * ( 4-1) = 3^3 * 3 = 27 *3 = 81

Add these together

0+3+18+81 =102

Answer 2

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▹ Answer

102

▹ Step-by-Step Explanation

Convert the notation into a sum and substitute values from 1-4:

(3¹⁻¹ *(1 - 1)) + (3²⁻¹ * (2 - 1)) + (3³⁻¹ * (3 - 1)) + (3⁴⁻¹ * (4 - 1))

0 + 3 + 18 + 81

= 102

Hope this helps!

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