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Vlad1618 [11]
3 years ago
6

These two pygons are similar. Z=what

Mathematics
1 answer:
marta [7]3 years ago
7 0

Answer:

I am not 100% about this, but I think that Z=46 Y=30 and X=45

Step-by-step explanation:

You might be interested in
Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8
Blababa [14]
w(s,t)=f(u(s,t),v(s,t))

From the given set of conditions, it's likely that you are asked to find the values of \dfrac{\partial w}{\partial s} and \dfrac{\partial w}{\partial t} at the point (s,t)=(1,0).

By the chain rule, the partial derivative with respect to s is

\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}

and so at the point (1,0), we have

\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21

Similarly, the partial derivative with respect to t would be found via

\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5
6 0
3 years ago
Which value of a would make the following expression completely factored?
ehidna [41]

Answer:

12

Step-by-step explanation:

x^2 - a

If a is a perfect square we could factor

x^2 - b^2 = (x-b)(x+b)

So a cannot be 36,49,81 since they are perfect squares

a must be 12

7 0
2 years ago
Solve for x.<br> 6 - 4x = -22
Kitty [74]

Answer:

x = 7

Step-by-step explanation:

6 - 4x = -22

-6          - 6

-4x = -28

x = -28/-4

x = 7

8 0
3 years ago
Use the compound interest formula A =​P(1 + ​r) t and the given information to solve for r.
Dmitry [639]

Answer:

Rounding to nearest hundredths gives us r=0.06.

So r is about 6%.

Step-by-step explanation:

So we are given:

A=P(1+r)^t

where

A=2300

P=1600

t=6.

A=P(1+r)^t

2300=1600(1+r)^6

Divide both sides by 1600:

\frac{2300}{1600}=(1+r)^6

Simplify:

\frac{23}{16}=(1+r)^6

Take the 6th root of both sides:

\sqrt[6]{\frac{23}{16}}=1+r

Subtract 1 on both sides:

\sqrt[6]{\frac{23}{16}}-1=r

So the exact solution is r=\sqrt[6]{\frac{23}{16}}-1

Most likely we are asked to round to a certain place value.

I'm going to put my value for r into my calculator.

r=0.062350864

Rounding to nearest hundredths gives us r=0.06.

8 0
3 years ago
In ΔEFG, g = 4.3 cm, e = 9.1 cm and ∠F=116°. Find the length of f, to the nearest 10th of a centimeter.
8_murik_8 [283]

Answer:

11.6

Step-by-step explanation:

6 0
3 years ago
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