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3 years ago

6

If h(c) = -4, then c =

1 answer:

klemol [59]3 years ago

8 0

Answer should be -4

since there is no other context, we can assume that x is -4.

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Solve by completing the square <br> X^2+12x-13=0

coldgirl [10]

I order to do this question, you need to put the 13 on the right side. So now you have x^2+12x+0=13. Now, take half of 12, and square it. Add this to both sides to get x^2+12x+36=49. Now factor the left side by putting the half of 12 into this blank to get, (x+_)^2=49. Final Answer is,
(x+6)^2=49.

7 0

3 years ago

Hree students were working on 630,000÷700 in math class.

xz_007 [3.2K]

Answer:

900

Step-by-step explanation:

900 is the answer i think so

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3 years ago

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nirvana33 [79]

Answer:B

Step-by-step explanation:

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3 years ago

Which system of linear inequalities Is represented by this graphed solution?

SashulF [63]

Answer:

y ≥ 3x - 1

y < $-\frac{1}{2}x+2$

Step-by-step explanation:

Let the equation of the solid line passing through (x', y') given in graph is,

y = mx + b

Here m = slope of the line

b = y-intercept

Slope of the solid line =

m = $\frac{3}{1}$

m = 3

y - intercept 'b' = -1

Therefore, equation of the line will be,

y = 3x - 1

Since, shaded (blue) area is above the line, inequality that will represent the solution area will be,

y ≥ 3x - 1

For the dotted line,

Slope of the line (m) = $\frac{\text{Rise}}{\text{Run}}$

= $\frac{-2}{4}$

= $-\frac{1}{2}$

y-intercept (b) = 2

Equation of the dotted line → y = $-\frac{1}{2}x+2$

Since, shaded (grey color) area is below the dotted line,

Inequality representing the solution area will be,

y < $-\frac{1}{2}x+2$

7 0

3 years ago

Find the least common denominator of 7/20 and 3/28

Genrish500 [490]

Answer:

140

Step-by-step explanation:

We have been given two fractions $\frac{7}{20}$ and $\frac{3}{28}$ . We are asked to find the least common denominator of both fractions.

To find the least common denominator of both fractions, we will find least common multiple of 20 and 28.

Prime factorization of 20: $2\times 2\times 5$

Prime factorization of 28: $2\times 2\times 7$

Least common multiple of 20 and 28 would be: $2\times 2\times 7\times 5=140$ .

Therefore, the least common denominator of both fractions would be 140.

7 0

3 years ago