Hi
.... then it is located on the perpendicular bisector.
Answer:
$840
Step-by-step explanation:
First, add 30 to 10.
Then, multiply your answer (40) by 21.
Finally, you get your final answer of $840.
Answer:
0.47 and 11.53
Step-by-step explanation:
h = 60t − 5t²
27 = 60t − 5t²
5t² − 60t + 27 = 0
Quadratic formula:
x = [ -b ± √(b² − 4ac) ] / 2a
t = [ -(-60) ± √((-60)² − 4(5)(27)) ] / 2(5)
t = (60 ± √3060) / 10
t = 0.47 or 11.53
First you have to make 7 a fraction, every fraction with the denominator 1 is a whole number, so 7 should be 7/1,
7/1×2/3
=14/3
=4 2/3
answer=4 2/3
hope this helps....
Integral of 2sin(2x) is -cos(2x)
from 0 to pi/2 (sub pi/2 minus sub 0 for x) and then solve
= -cos(2*pi/2)-(-cos0)
= -cos pi + cos 0
= 1 + 1
= 2
