Which kind of molecule must be labeled to make radioactively labeled DNA
2 answers:
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The value of 2pg in the given population is 0.432
<u>Explanation:</u>
Given:
C is normal
c is curly wings
So the homozygous dominant condition would be CC
Heterozygous condition would be Cc
Recessive condition would be cc
According to Hardy Weinberg principle,
p² + 2pq + q² = 1
and
p + q = 1
Here,
q² = cc = 100
q² = 100 / 1000
q = √0.1
q = 0.316
So,
p + q = 1
p + 0.316 = 1
p = 0.684
Thus, 2pq would be:
Therefore, the value of 2pg in the given population is 0.432