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lord [1]
3 years ago
11

Plesssssssssss help has to be done by 12:40

Mathematics
2 answers:
dimulka [17.4K]3 years ago
6 0

the answer is E

distribute and solve

NeTakaya3 years ago
3 0

Answer:

I pretty sure I answered this for you like 10-15 minutes ago

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A student measures the diameter of a small cylindrical object and gets the following readings: 4.32, 4.35, 4.31, 4.36, 4.37, 4.3
Keith_Richards [23]

Answer:

The average of the diameter readings is 4.34 cm.

Step-by-step explanation:

We  are given the following data set(cm):

4.32, 4.35, 4.31, 4.36, 4.37, 4.34

Formula:

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{26.05}{6} = 4.34167 \approx 4.34

Thus, the average of the diameter readings is 4.34 cm.

8 0
4 years ago
Im Not completely sure what this is asking, but can someone please help answer this
solmaris [256]

Answer:

the answer is 60

Step-by-step explanation:

because 2(30)=60

7 0
3 years ago
Factor -4 out of -8d+20
Kazeer [188]

Answer:

-4(2d-5)

Step-by-step explanation:

-8d+20

-4(2d-5)

8 0
3 years ago
Which are the solutions of he quadratic equation ? x2 = 9x + 6
dedylja [7]
Put everything on the same side of the equals sign and set it equal to zero so you can factor it.  x^{2} -9x-6=0.  In order to factor that you have no choice really but to put it into the quadratic formula.  When you do that you find that your zeros are x = 9.623475383 and -.623475383
4 0
4 years ago
Read 2 more answers
What are the zeros of the quadratic function f(x) = 2x2 + 8x – 3? x = –2 – StartRoot StartFraction 11 Over 2 EndFraction EndRoot
Phantasy [73]

Answer:

The zeros are

x=-2+\frac{\sqrt{22}}{2}

x=-2-\frac{\sqrt{22}}{2}  

Step-by-step explanation:

we have

f(x)=2x^{2}+8x-3

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

Equate the function to zero

2x^{2} +8x-3=0  

so

a=2\\b=8\\c=-3

substitute in the formula      

x=\frac{-8\pm\sqrt{8^{2}-4(2)(-3)}} {2(2)}  

x=\frac{-8\pm\sqrt{88}} {4} 

x=\frac{-8\pm2\sqrt{22}} {4} 

x=-2\pm\frac{\sqrt{22}}{2}

therefore

x=-2+\frac{\sqrt{22}}{2}

x=-2-\frac{\sqrt{22}}{2}  

4 0
4 years ago
Read 2 more answers
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