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3 years ago

What is the solution set for this inequality?

Mathematics

2 answers:

enyata [817]3 years ago

8 0

Answer:

It's A

Step-by-step explanation:

You have to subtract 40 from both sides

Then divide both sides by 8

And then you have your answer.

NikAS [45]3 years ago

4 0

A x>7 Isolate the variable by dividing each side by factors that don't contain the variable.

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If Gabby has 15 cosmetics in a bag, and 5 of those cosmetics are eyeshadow, then what is the probability of her picking an eyesh

nasty-shy [4]

this could be represented in the following way 5/15

Probability is

Fraction= 1/3

Decimal=0.33333333333333

Percentage:33.33333%

4 0

3 years ago

Read 2 more answers

Divide, if possible, and check. If the quotient is undefined, state this -12.6\(-2)

OleMash [197]

The answer is 6.3
-12.6/-2=6.3

7 0

3 years ago

PLEASE HELP ILL GIVE BRAINLIEST

DanielleElmas [232]

Option A:

$(x-5)^{2}+(y-3)^{2}=16$

Solution:

Given data:

Center of the circle is (5, 3).

Radius of the circle = 4

To find the equation of the circle:

The general form of the equation of a circle in centre-radius format is

$(x-h)^{2}+(y-k)^{2}=r^{2}$

where (h, k) is the centre of the circle and r is the radius of the circle.

Substitute the given values in the equation of a circle formula:

$(x-5)^{2}+(y-3)^{2}=4^{2}$

$(x-5)^{2}+(y-3)^{2}=16$

The equation of the given circle is $(x-5)^{2}+(y-3)^{2}=16$ .

Hence Option A is the correct answer.

5 0

2 years ago

Please help with math

irakobra [83]

Answer:

5 and 6

Step-by-step explanation:

You have to find two numbers (in the chart) that have a difference of 3/8.

This is just one possiblity, there are other correct answers.

There is size 5 and 6. 9 and 4/8-9 and 1/8=3/8.

8 0

3 years ago

Simplify without the absolute value |x+3| ; if x>2

inna [77]

Answer:

$x+3$ if $x>2$

Step-by-step explanation:

Recall some following basic ideas about absolute value:

$|0|=0$ or I guess $-(0)=0$

$|3|=3$

$|-3|=-(-3)$ or just $3$ but there is a reason why I wrote it the way I did.

You see that the absolute value returned the same value if the value was positive.

You see that the absolute value returned the opposite value if the value was negative.

You can include 0 in either.

Let's look at $|x+3|$ alone for a second.

* $|x+3|=x+3$ if $x+3$ is positive or zero.

When is $x+3$ positive or zero? [greater than or equal to 0]

$x+3\ge 0$

Subtract 3 on both sides

$x\ge -3$

* $|x+3|=-(x+3)$ if $x+3$ is negative or zero.

When is $x+3$ negative or zero? [less or equal to 0]

$x+3\le 0$

Subtract 3 on both sides

$x\le -3$

So looking at the bullet points (the *), $x>2$ fits into the first inequality.

Therefore, $|x+3|=x+3$ .

8 0

2 years ago