Hello!
A force of 5 N produces an acceleration of 2 m/s2 on the object. What is the mass of the object ?
Data:
F (force) = 5 N
m (mass) = ?
a (acceleration) = 2 m/s²
Solving:





Answer:
2.5 kg
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I Hope this helps, greetings ... Dexteright02! =)
The work she on the box will be 40 J. Here the displacement due to the force is height.
<h2 /><h3>What is work done?</h3>
Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.
Given data;
Force,F = 80 N
height, h = 0.5 m
Work,W = ? J
Here the displacement is height;
W = F × d
W = F × h
W = 80 N × 0.5 m
W = 40 Nm
W=40 J
Hence work she on the box will be 40 J.
To learn more about the work done refer to the link;
brainly.com/question/3902440
#SPJ1
Answer:
83.1946504051 m
Explanation:
u = Initial velocity = 
s = Displacement = 
= Angle = 

Coefficient of friction



The stopping distance is 83.1946504051 m
Answer:
The width is 
Explanation:
From the question we are told that
The width of the slit is 
The wavelength of the light is 
The position of the screen is 
Generally angle at which the first minimum of the interference pattern the light occurs is mathematically represented as
![\theta = sin ^{-1}[\frac{m \lambda}{d} ]](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%20sin%20%5E%7B-1%7D%5B%5Cfrac%7Bm%20%5Clambda%7D%7Bd%7D%20%5D)
Where m which is the order of the interference is 1
substituting values
![\theta = sin ^{-1}[\frac{1 *721*10^{-9}}{ 77.7*10^{-6}} ]](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%20sin%20%5E%7B-1%7D%5B%5Cfrac%7B1%20%2A721%2A10%5E%7B-9%7D%7D%7B%2077.7%2A10%5E%7B-6%7D%7D%20%5D)

Now the width of first minimum of the interference pattern is mathematically evaluated as

substituting values


Now the width of the pattern's central maximum is mathematically evaluated as

substituting values


The average velocity of the object would be :
[s (1.5) - s (1)] / 0.5
= [8.75 -15] / 0.5
= 12.5 m/s
Hope this helps