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3 years ago

12

Plzzzzzz helpppp asap why the hell do peaple not answer

1 answer:

o-na [289]3 years ago

6 0

Answer:

The base is 10 squares by 5 squares

Step-by-step explanation:

Well 18m is three squares so 18/3 = 6m which is 6m per square

The manor is 60m by 30m

so 60/6 = 10

and 30/6= 5

The base is 10 squares by 5 squares

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Decide which title best describes all of the expressions in each column of the table. Place the correct title at the top of each

irga5000 [103]

For the first one is has greater then 3 terms
The middle one is has exactly one term
And the last one is has two terms
I believe I hope this helps

4 0

3 years ago

Integrate the following. ∫<img src="https://tex.z-dn.net/?f=5x%5E%7B4%7D%20dx" id="TexFormula1" title="5x^{4} dx" alt="5x^{4} dx

Vadim26 [7]

Answer:

$\displaystyle D) {x}^{5} + \rm C$

Step-by-step explanation:

we would like to integrate the following Integral:

$\displaystyle \int 5 {x}^{4} \, dx$

well, to get the constant we can consider the following Integration rule:

$\displaystyle \int c{x} ^{n} \, dx = c\int {x}^{n} \, dx$

therefore,

$\displaystyle 5\int {x}^{4} \, dx$

recall exponent integration rule:

$\displaystyle \int {x} ^{n} \, dx = \frac{ {x}^{n + 1} }{n + 1}$

so let,

$n = 4$

Thus integrate:

$\displaystyle = 5\left( \frac{ {x}^{4+ 1} }{4 + 1} \right)$

simplify addition:

$\displaystyle = 5\left( \frac{ {x}^{5} }{5} \right)$

reduce fraction:

$\displaystyle = {x}^{5}$

finally we of course have to add the constant of integration:

$\displaystyle \boxed{ {x}^{5} + \rm C}$

hence,

our answer is D)

7 0

3 years ago

Read 2 more answers

Which number is greater . 84 or 9.3

tatuchka [14]

I think the answer is 9.3, but I’m not sure

3 0

3 years ago

Read 2 more answers

A particle moves along the x-axis so that at any time t, t ≥ 0, its acceleration is a(t) = -4sin(2t). If the velocity of the par

sasho [114]

The velocity of the particle is given by

$v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du$

Since $a(t)=-4\sin2t$ and $v(0)=7$ , we get

$\displaystyle\int_0^ta(u)\,\mathrm du=\int_0^t-4\sin2u\,\mathrm du=2\cos2u\bigg|_0^t=2\cos2t-2$

$\implies v(t)=2\cos2t+5$

Similarly, the position function is obtained via

$x(t)=x(0)+\displaystyle\int_0^tv(u)\,\mathrm du$

We know $v(t)$ and we're told that $x(0)=0$ , so

$\displaystyle\int_0^tv(u)\,\mathrm du=\int_0^t(2\cos2u+5)\,\mathrm du=\sin2u+5u\bigg|_0^t=\sin2t+5t$

$\implies x(t)=\sin2t+5t$

making the answer A.

3 0

3 years ago

Solve 4 + 2 sinx= 14-8 sinx for 0° ≤ x ≤ 180

Oduvanchick [21]

<h2>Answer:</h2>

<u>x= 90°</u>.

<h2>Step-by-step explanation:</h2>

<h3>1. Write the expression.</h3>

$4 + 2 sin(x)= 14-8 sin(x)$

<h3>2. Subtract "4" from both sides of the equation.</h3>

$-4+4 + 2 sin(x)= 14-8 sin(x)-4\\ \\2 sin(x)= 10-8 sin(x)$

<h3>3. Add "8sin(x)" to both sides of the equation.</h3>

$2 sin(x)+8 sin(x)= 10-8 sin(x)+8 sin(x)\\ \\10 sin(x)= 10$

<h3>4. Divide both sides by 10.</h3>

$\frac{10 sin(x)}{10} = \frac{10}{10} \\ \\sin(x)=1$

<h3>5. Apply the arcsin of sin^-1 to both sides of the equation.</h3>

$arcsin(sin(x))=arcsin(1)\\ \\x=90$

<h3>6. Conclude.</h3>

<u>x= 90°</u>.

3 0

2 years ago