3x−8 ≤ 23 OR −4x+26≥6 find x

The sea turtle habitat at the zoo is made by connecting two large aquariums. The first aquarium is 6\text { m}6 m6, space, m lon

iren [92.7K]

First aquarium dimensions:

Length = 6 m.

Width = 4 m and

Height = 2 meter.

Second aquarium dimensions:

Length = 8 m.

Width = 9 m and

Height = 3 meter.

We know formula for volume of a cuboidal box = Length*Width*Height.

Plugging values of length, width and height of first aquarium in formula of volume. We get

V1 = 6*4*2 = 48 m^3.

Plugging values of length, width and height of second aquarium in formula of volume. We get

V2 = 8*9*3 = 216 m^3.

In order to find the total cubic meters of space do the sea turtles have in their habitat, we need to add both volumes.

Therefore, Total voulme of both aquarium = V1 +V2 = 48+216 = 264 m^3.

Therefore, total 264 m^3 cubic meters of space the sea turtles have in their habitat.

8 0

3 years ago

Please answer this question now

Nookie1986 [14]

Answer:

Arc BC = 117°

Step-by-step explanation:

Angle D is an inscribed angle that intercepts arc ABC. According to the Inscribed angle theorem of a circle, m<D = ½ of arc ABC.

Thus,

104° = ½(AB + BC)

104° = ½(91° + BC)

Multiply both sides by 2

104*2 = 91 + BC

208 = 91 + BC

Subtract both sides by 91

208 - 91 = BC

117 = BC

Arc BC = 117°

4 0

3 years ago

Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.

Sindrei [870]

Answer:

a) $P(X=3) = 0.1$

b) $P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

c) $P(X=4) = 0.3$

d) $P(X=0) = 0.2$

e) $E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

f) $E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

Step-by-step explanation:

We have the following distribution

x 0 1 2 3 4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

$P(X=3) = 0.1$

Part b

We want this probability:

$P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

Part c

For this case we want this probability:

$P(X=4) = 0.3$

Part d

$P(X=0) = 0.2$

Part e

We can find the mean with this formula:

$E(X)= \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

Part f

We can find the second moment with this formula

$E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

4 0

4 years ago

Which is a zero of x2 − 8 = 2x?

Nastasia [14]

Answer:

The zeros are x=4, -2

Step-by-step explanation:

Its zeros can be found by setting the function to zero. The values of x that represent the set equation are the zeroes of the function. To find the zeros of a function, find the values of x where f(x) = 0.

Hope this helped!!!!

5 0

3 years ago

How would get the area?

yuradex [85]

Answer:

x > 5

Step-by-step explanation:

Formula: length x width

First, you must substitute in the numbers.

16-2x*10 < 60

Work:

(16-2x)10 < 60

Then, distribute the 10 to the 16 and to the 2x.

160-20x < 60

Next, substract 160 from both sides.

-20x < -100

Now, divide -20 from both sides.

x < 5

This isn't the answer yet because you have to flip the sign because you divided by a negative.

x > 5

8 0

3 years ago

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