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3 years ago

What is the third quartile, Q3, of the data represented by the box plot?

Mathematics

1 answer:

Andre45 [30]3 years ago

8 0

The answer is 65 your welcome

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Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a

mihalych1998 [28]

Answer:

y = 4.125x + 496.25

Step-by-step explanation:

Set the data up as points. Then deal with the points.

Givens

(30,620)

(70,785)

y2 = 785

y1 = 620

x2 = 70

x1 = 30

Formula

Slope = (y2 - y1) / (x2 - x1)

Solution

Slope = (785 - 620)/(70 - 30)

Slope = 165 / 40

Slope = 4.125

===================

Now you need the y intercept. Either one of the two given points will give you that.

y = 620

x = 30

m = 4.125

y = mx + b

620 = 4.125*30 + b

620 = 123.75 + b

620 - 123.75 + b

b = 496.25

5 0

3 years ago

34 is what percent of 80? (Round to the nearest whole number)

Marizza181 [45]

Answer:

42.5

34:80*100 =

(34*100):80 =

3400:80 = 42.5

8 0

3 years ago

Show work please A 18 B 2 C 9 D 1

NeTakaya

Answer:

Step-by-step explanation:

the need to equal the same and none of the lower numbers work

6 0

3 years ago

What is the equation of the line that contains the two points (0,-1) and (-1,-3)?

Nady [450]

The answer is in this picture

4 0

3 years ago

Read 2 more answers

Please hepl with math

Ivenika [448]

Answer:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}$

Step-by-step explanation:

We are given the expression to be simplified:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}}$

Let us take common a term with a power of 5 from the numerator and the denominator of the given expression.

We know that:

$a^{p+q} = a^p \times a^q$

Let us use it to solve the powers of 5 in the given expression.

$\therefore$ we can write:

$5^{n+2} = 5^{n+1}\times 5= 5^n\times 5^{2}$

$5^{n+1} = 5^n\times 5$

The given expression becomes:

$\dfrac{5^{n+1} \times 5-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n}\times 5}$

Taking common $5^{n+1}$ from the numerator and

Taking common $5^{n}$ from the denominator

$\Rightarrow \dfrac{5^{n+1} (5-6)} {5^{n}(13-2\times5)}\\\Rightarrow \dfrac{5^{n+1} (-1)} {5^{n}(13-10)}\\\Rightarrow -\dfrac{5^{n+1}} {5^{n}\times3}\\\Rightarrow -\dfrac{5^{n}\times 5} {5^{n}\times3}\\\Rightarrow -\dfrac{5}{3}$

$\therefore$ The answer is:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}$

6 0

3 years ago