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bezimeni [28]
3 years ago
9

What is the third quartile, Q3, of the data represented by the box plot?

Mathematics
1 answer:
Andre45 [30]3 years ago
8 0
The answer is 65 your welcome
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Step-by-step explanation:

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What is 11/12 - 2/3 <br> Subtracting Proper Fractions
alexgriva [62]

Answer:

0.25

Step-by-step explanation:

11/12 = 0.917

2/3 = 0.667

0.917 - 0.667 = 0.25

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umka2103 [35]

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Step-by-step explanation:

5 0
2 years ago
If PN=29cm and MN=13 , then PM=?
HACTEHA [7]

*see attachment for the figure referred to

Answer/Step-by-step explanation:

1. PN = 29

MN = 13

PM = ?

PN = PM + MN (Segment addition postulate)

PN - MN = PM (subtract MN from each side)

29 - 13 = PM (substitute)

16 = PM

PM = 16 cm

2. PN = 34, MN = 19, PM = ?

PN = PM + MN (sediment addition postulate)

PN - MN = PM (subtract MN from each side)

34 - 19 = PM (substitute)

15 = PM

PM = 15 cm

3. PM = 19, MN = 23, PN = ?

PN = PM + MN (Segment addition postulate)

PN = 19 + 23 (substitute)

PN = 42 cm

4. MN = 82, PN = 105, PM = ?

PN = PM + MN (segment addition postulate)

PN - MN = PM (subtract MN from each side)

105 - 82 = PM (substitute)

23 = PM

PM = 23 cm

5. PM = 100, MN = 100, PN = ?

PN = PM + MN (Segment addition postulate)

PN = 100 + 100 (substitute)

PN = 200 cm

7 0
3 years ago
Find the values of x and y.
vova2212 [387]

Look at the picture.

We have the equation (1) 12x + 4y = 40.

We know, the sum of the acute angles in a right triangle is 90°.

Therefore we have the equation (2) (12x + 4y) + (17x - y) = 90

Substitute (1) to (2):

40 + 17x - y = 90        <em>subtract 40 from both sides</em>

17x - y = 50   (3)

We have the system of equations:

\left\{\begin{array}{ccc}12x + 4y = 40&|:4\\17x-y=50\end{array}\right\\\underline{+\left\{\begin{array}{ccc}3x + y = 10\\17x-y=50\end{array}\right}\ \text{add both side of equations}\\.\qquad20x=60\qquad|:20\\.\qquad x=3

Substitute the value of x to (3)

17(3)-y=50\\51-y=50\qquad|-51\\-y=-1\to y=1

Answer: x = 3 and y = 1.

4 0
2 years ago
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