Can u help me pleeeeeeeeeeeease
1 answer:
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Answer:
The variable, y is 11°
Step-by-step explanation:
The given parameters are;
in triangle ΔABC; in triangle ΔFGH;
Segment = 14
Segment
= 14
Segment = 27
Segment
= 19
Segment = 19
Segment
= 2·y + 5
∡A = 32° ∡G = 32°
∡A = ∠BAC which is the angle formed by segments = 14 and
= 19
Therefore, segment = 27, is the segment opposite to ∡A = 32°
Similarly, ∡G = ∠FGH which is the angle formed by segments = 14 and
= 19
Therefore, segment = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;
≅
by Congruent Parts of Congruent Triangles are Congruent (CPCTC)
∴ =
= 27° y definition of congruency
= 2·y + 5 = 27° by transitive property
∴ 2·y + 5 = 27°
2·y = 27° - 5° = 22°
y = 22°/2 = 11°
The variable, y = 11°