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solniwko [45]
3 years ago
15

12r2s + 21rs2 – 3rs=

Mathematics
1 answer:
Nitella [24]3 years ago
6 0
Answer:
63rs

explanation:
collect like terms
12*2=24rs
21*2=42rs
then add 24+42=66rs
then subtract 3rs
then just add rs
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the length of an arc of a circle is 1/5 of its circumference. if the area of the circle is346.5cm²,find the angle subtended by t
dexar [7]

Answer:

72°

Step-by-step explanation:

From the question,

Area of the circle = πr²

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Given: A = 346.5 cm², π = 3.14

r = √(346.5/3.14)

r = √(110.35)

r = 10.5 cm.

Therefore,

circumference of the circle = 2πr = 2×3.14×10.5

circumference = 65.94 m

If the length of the arc(s) is 1/5 of its circumference.

Therefore, length of arc (s) = 13.188

⇒ length of arc/circumference = 13.188/65.94 =  1/5

s/2πr = θ/360

Where θ = angle substends at the center of the circle

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3 0
3 years ago
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kati45 [8]

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