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gavmur [86]
3 years ago
14

Solve the system by graphing. Select the solution(s). y = x + 2 y = 0.5(x + 2)

Mathematics
1 answer:
faltersainse [42]3 years ago
4 0

Answer:

Part 1) The solution is the point (-2,0)

Part 2) The solutions are the points (-2,0) and (0,2)

Step-by-step explanation:

Part 1

we have

y=x+2 -----> equation A

y=0.5(x+2) ----> y=0.5x+1 ---> equation B

Solve the system by graphing

Remember that the solution of the system is the intersection point both graphs

using a graphing tool

The solution is the point (-2,0)

see the attached figure N 1

Part 2

we have

y=x+2 -----> equation A

y=0.5(x+2)^2 ----> equation B

Solve the system by graphing

Remember that the solution of the system are the intersection points both graphs

using a graphing tool

The solutions are the points (-2,0) and (0,2)

see the attached figure N 2

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If BC = 61 and AB = 82, what is the length of AC?
Nitella [24]

Answer:

54.8

Step-by-step explanation:

Pythagorean theorem is a^2+b^2=c^2.

Plug the given values in to get 61^2+b^2=82^2

61^2 is 3,721 and 82^2 is 6,724.

6,724-3,721 is 3,003.

The square root of 3,003, rounded to a reasonable value, is 54.8.

The length of AC is 54.8.

4 0
3 years ago
CAN UHELP PLEASE???? I NEED HELP AND I CAN TAKE THETEST ONLT ONE TIME !PLLLLZZZZZ!
marusya05 [52]
Well add them all up. : 10+15+8+7=40. There are 8 white balls out of 40. 8/40. Find the GCF of them both and simplify them.

8=8 so 8/8 = 1
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B. is your answer.

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4 0
3 years ago
Read 2 more answers
Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.
MrMuchimi
A random variable following a binomial distribution over n trials with success probability p has PMF

f_X(x)=\dbinom nxp^x(1-p)^{n-x}

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1

The mean is given by the expected value of the distribution,

\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}
\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}
\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}
\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}

The remaining sum has a summand which is the PMF of yet another binomial distribution with n-1 trials and the same success probability, so the sum is 1 and you're left with

\mathbb E(x)=np=126\times0.27=34.02

You can similarly derive the variance by computing \mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2, but I'll leave that as an exercise for you. You would find that \mathbb V(X)=np(1-p), so the variance here would be

\mathbb V(X)=125\times0.27\times0.73=24.8346

The standard deviation is just the square root of the variance, which is

\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834
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3 years ago
Which expression is equivalent to 3x/x+1 divided by x + 1?
kiruha [24]
I hope this helps you.

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What is 28/77 in simplest form
Musya8 [376]
4/11 because it is divisible by seven
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