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Zigmanuir [339]
3 years ago
11

PLEASE HELP I ONLY HAVE ONE HOUR PLEASE HELP PLEASE

Mathematics
1 answer:
max2010maxim [7]3 years ago
7 0



graph 0,2
graph 3,4
graph 0,3

I REALLY HOPE IM RIGHT AND THAT WORKS

MAKE SURE THAT THE ANSWER I GAVE IS GOING IN A STRAIGHT LINE DIAGONALLY
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Evaluate the integral using integration by parts with the indicated choices of u and dv. (Use C for the constant of integration.
Aleksandr-060686 [28]

Take

u=\ln x\implies\mathrm du=\dfrac{\mathrm dx}x

\mathrm dv=4x^2\,\mathrm dx\implies v=\dfrac43x^3

Then

\displaystyle\int4x^2\ln x\,\mathrm dx=\frac43x^3\ln x-\frac43\int x^2\,\mathrm dx=\frac43x^3\ln x-\frac49x^3+C

=\boxed{\dfrac49x^3(3\ln x-1)+C}

5 0
3 years ago
NEED HELP, PLEASE SHOW WORK. :(((
sukhopar [10]

Answer:

About 34 workers

Step-by-step explanation:

200/30 to find on average how many trees can be carved by one worker

The answer is 6.666, so just 6

Then 6*4=24 to figure out how many more trees can be carved by (4 more) workers

So, add 4 to 30 and about 224 trees can be carved.

8 0
3 years ago
Find the roots of each equation by factoring
Korolek [52]

Answer:

x=7 x=-7

Step-by-step explanation:

Solution is attached.

7 0
3 years ago
I beg you help me plz
Neporo4naja [7]

Step-by-step explanation:

I think geomatory box is also similar to original figure

5 0
3 years ago
A square with sides of 3 squareroot 2 is inscribed in a circle. what is the area of one of the sectors formed by the radii to th
mrs_skeptik [129]
Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2).  Draw this to verify this statement.  Note that the height of each such triangular area is (3 sqrt(2))/2.

So now we have the base and height of one of the triangular sections.

The area of a triangle is A = (1/2) (base) (height).  Subst. the values discussed above,   A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2).  Show that this boils down to A = 9/2.

You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section.   Doing the problem this way, we get (1/4) (3 sqrt(2) )^2.  Thus, 
A = (1/4) (9 * 2) = (9/2).  Same answer as before. 
4 0
3 years ago
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