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Pavel [41]
3 years ago
15

The graphs of y = –7x + 12 and y = 2/3x –2/3 are shown. Which region describes the solution of the system of inequalities y ≤ –7

x + 12 and y ≤ –2/3x –2/3 ?

Mathematics
1 answer:
kobusy [5.1K]3 years ago
3 0
You can draw both lines y=-7x+12 and y=-2/3x –2/3 and define which part of the plane satisfies the unequalities y ≤ –7x + 12 and y ≤ –2/3x –2/3. For example, choosing point (0,0) you can see that
0 ≤ –7·0 + 12 (is true) and 0 ≤ –2/3·0 –2/3 (is false). This means that (0,0) is a solution of the first unequality and isn't a solution of the second unequality, hence (0,0) belongs to the shaded part of the plane defined by the first unequality and doesn't belong to the shaded part defined by the second unequality. Both (black on the image) parts intersect and the common area (red on the picture) is the <span>region that describes the solutions of the system of inequalities.</span>

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MariettaO [177]

Answer:

4.\ \sin E = \cos G

Step-by-step explanation:

Given

\triangle EFG

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Required

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Collect like terms

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2 years ago
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The mean of 14 numbers is 49. Removing one of the numbers causes the mean to decrease to 43. What number was removed?
Mademuasel [1]

Answer:

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Step-by-step explanation:

The total before division took place was

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mean = 49

Total = 49 * 14

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Now you subtract x from the total

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And divide by 13 [one number is missing]

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and the result = 43

(685 - x ) / 13 = 43                Multiply both sides by 13

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685 - x = 559                       Subtract 685 from both sides

- x = - 126                             Multiply by - 1

x = 126

4 0
2 years ago
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