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kaheart [24]
4 years ago
15

How much does 3.75 kg of chocolate cost if 0.7 kg of it costs $4.20?

Mathematics
2 answers:
const2013 [10]4 years ago
8 0

Answer:

22.50

Step-by-step explanation:

first divide 3.75 by 0.7 and then multiply by 4.20

vesna_86 [32]4 years ago
6 0
<h2>3.75 kg chocolate costs 21 $</h2>

Step-by-step explanation:

Cost of 0.70 kg chocolate = 4.20 $

\texttt{Cost of 1 kg chocolate =}\frac{4.20}{0.70}=6\$

Now we need to find cost for 3.75 kg chocolate.

Cost for 3.75 kg chocolate = Cost of 1 kg chocolate x 3.75

Cost for 3.75 kg chocolate = 6 x 3.75

Cost for 3.75 kg chocolate = 21 $

3.75 kg chocolate costs 21 $        

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Solve the equation by completing the square x^2-3x-18=0
Alexandra [31]

Answer:

x = -3, 6

Step-by-step explanation:

First, add 18 to both sides

x² - 3x - 18 = 0

           + 18    + 18

x² - 3x = 18

Add 9/4 to both sides because that is the square of half of -3

x² - 3x + 9/4 = 18 + 9/4

Multiply both sides by 4 to get rid of the fractions

(x² - 3x + 9/4 = 18 + 9/4)4

4x² - 12x + 9 = 72 + 9 = 81

Factor the left side of the equation

(2x - 3)² = 81

√(2x - 3)² = √81

Because of the square root, this will result in a positive number and a negative number

2x - 3 = 9

2x - 3 = -9

For both equations, add 3 to both sides then divide by 2

2x - 3 = 9

     + 3   +3

2x = 12

2x/2 = 12/2

x = 6

2x - 3 = -9

    + 3   + 3

2x = -6

x = -3

4 0
2 years ago
Without completing decide whether the value of each expression is on is much smaller than 1 close to 1 or much greater than 1
xxMikexx [17]

Answer:

Step-by-step explanation:

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3) Less

4) Less

5)Less

6) Close

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3 years ago
An area of 4 square yards is equal to 36 square feet. 10 square yards is equal to how many square feet?
Debora [2.8K]

Answer:

90 square feet

Step-by-step explanation:

36 square feet divided by 4 square yards equals to 9 square feet for 1 square yard.

9 square feet times 10 square yards equals to 90 square feet.

8 0
3 years ago
Read 2 more answers
A little confusing help please
UkoKoshka [18]

Answer:

Its 63...I just took the same test on ALEKS

Step-by-step explanation:

6 0
3 years ago
Which two statements are missing in steps 3 and 4? ∠X ≅ ∠C △ABC ~ △ZYX by the SAS similarity theorem. ∠B ≅ ∠Y △ABC ~ △ZYX by the
Zepler [3.9K]

Solution:

We have to prove that ,

△ABC ~ △Z Y X   Using SAS.

It is given that , ∠X ≅ ∠C .

You must keep in mind when two triangles are similar by S A S

1. The included side between the angle should be Proportional.

   \frac{BC}{XY}=\frac{AC}{XZ}

2. We have to prove that ,

△ABC ~ △Z Y X   Using SAS.

It is given that , ∠B ≅ ∠Y .

The included side between the given angle should be Proportional.

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3. We have to prove that ,

△ABC ~ △Z Y X   Using SSS.

The three sides of two triangles must be Proportional.

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7 0
3 years ago
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