when we divides m(x) ÷n(x) quotient and remainder is
Step-by-step explanation:
Total Surface area of a pyramid is given as
= Lateral surface area + area of base.
Lateral surface area = 1/2×perimeter of base×slant height
given the base is square with side 9 in , and slant height of 12 inches.
therefore, LSA = 1/2(9*4)×12 = 216 in^2
Now, TSA = LSA + Base area = 216+9^2 = 297 in^2
a) It is given that the pyramid is smaller therefore, it will require lesser paint than the original pyramid ( The TSA of the smaller pyramid cannot be calculated as its dimentions are not given).
b) It can not be solved as dimensions are missing in the question.
However, the logic has been explained in the soluion one easily put values to find the solution.
Answer:
y-1=5(x+6)
Step-by-step explanation:
Point slope:
(y-y1)=slope(x-x1)
y-1=5(x+6)
Hope this helps!
X-4y=-12
4x-y=12
eliminate y's
multily 2nd equaiton by -4 and add to top one
x-4y=-12
<u>-16x+4y=-48 +
</u>-15x+0y=-60
-15x=-60
divide both sides by -15
x=4
sub back
x-4y=-12
4-4y=-12
minus 4 both sides
-4y=-16
divide both sides by -4
y=4
x=4
y=4
(x,y)
(4,4)<u>
</u>
1350 cm^2. First, we must find the area of one side. The formula for the area of a square is S^2 or S*S, so plugging in the value of the side we get 15*15=225. So each side of the cube is 225 cm^2, so since there are 6 sides, we just multiply by 6 (225*6=1350).
