${9}^{ \frac{3}{2} } \times {27}^{ \frac{1}{2} } = {(3)}^{ \frac{3}{2} \times 2 } \times {(3)}^{ \frac{1}{2} \times 3} \\ = {3}^{3} \times {3}^{ \frac{3}{2} } \\ = {3}^{3 + \frac{3}{2} } \\ = {3}^{4\frac{1}{2} } \\ = {3}^{ \frac{9}{2} }$

8 0

2 years ago

PLEASE PLEASE HELP !!!!!!!!

nataly862011 [7]

Answer:c

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Please answer asap!!

Bezzdna [24]

Answer:

.10

Step-by-step explanation:

3 0

2 years ago

PLS HELP MEEEE

balandron [24]

Answer:

Answer is D 2x^3 + 7x^2 - 23x + 12

Step-by-step explanation:

(x^2 + 5x - 4)(2x - 3)

Expand by multiplying each term in the first expression by each term in the second expression.

The easy way would be multiplying the first expression by 2x then set those numbers off to the side.

Then multiply the first expression by -3 and set those numbers off to the side as well.

Then add the numbers you put off to the side together.

This should result in: 2x^3 - 3x^2 + 10x^2 - 15x - 8x + 12

Combine the alike terms together

=2x^3 + 7x^2 -23x + 12

7 0

3 years ago

Read 2 more answers