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inna [77]
3 years ago
10

What is the output value for the following function if the input value is 3.2?

Mathematics
1 answer:
mars1129 [50]3 years ago
3 0
For functions, there is only many input values, but there can be only one output value, and there can be no identical x values. For this, x=3.2. If y= 2*3.2 - 1, then y=5.4.
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Prove the following statement.
gayaneshka [121]

Answer:

You can prove this statement as follows:

Step-by-step explanation:

An odd integer is a number of the form 2k+1 where k\in \mathbb{Z}. Consider the following cases.

Case 1. If k is even we have: (2k+1)^{2}=(2(2s)+1)^{2}=(4s+1)^{2}=16s^2+8s+1=8(2s^2+s)+1.

If we denote by m=2s^2+2 we have that (2k+1)^{2}=8m+1.

Case 2. if k is odd we have: (2k+1)^{2}=(2(2s+1)+1)^{2}=(4s+3)^{2}=16s^2+24s+9=16s^{2}+24s+8+1=8(2s^{2}+3s+1)+1.

If we denote by m=2s^{2}+24s+1 we have that (2k+1)^{2}=8m+1

This result says that the remainder when we divide the square of any odd integer by 8 is 1.

6 0
3 years ago
Find the distance between the two given points. (-6, -5) and (2, 0)
Ipatiy [6.2K]

Answer:

The answer is

<h2>\sqrt{41}  \:  \:  or \:  \:  \: 6.403 \:  \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{( {x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-6, -5) and (2, 0)

The distance is

d =  \sqrt{ ({ - 6 - 2})^{2} +  ({ - 5 - 0})^{2}  }  \\  =  \sqrt{ ({ - 4})^{2}  +  ({ - 5})^{2} }  \\  =  \sqrt{16 + 25}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

We have the final answer as

\sqrt{41}  \:  \:  or \:  \:  \: 6.403 \:  \:  \: units

Hope this helps you

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3 years ago
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The answer is (4,-4).
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What is the complete question and what are the choices??
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