Which of the following gives a single solution of the |x+3|- 2

the initial cost to set up a website is $48. it cost $44 per month to maintain the website . how many months will you be able to

Delicious77 [7]

We would start with 400 - 48, to cover the initial cost. We would be left with 352 dollars to spare for the monthly bill. 352 divided by 44, which is the monthly cost, would be 8. The website could be set up and held for 8 or 9 months, depending on if the initial cost is paid at the same time or before the first monthly one.

8 0

3 years ago

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An architect is sketching a blueprint of a patio for a new fence. On the blueprint, C is the midpoint of segment AD. Point B is

Slav-nsk [51]

The length of AD is 32 feet

Step-by-step explanation:

An architect is sketching a blueprint of a patio for a new fence

On the blueprint, C is the midpoint of segment AD
Point B is the midpoint of segment AC
BC = 8 feet

We need to find the length of AD

A mid-point divides a line segments into two equal parts in length

∵ C is the mid-point of AD

- The mid-point C divides the line segments AD into two equal parts

∴ AC = CD

∵ B is the mid point of AC

∴ AB = BC

∵ BC = 8 feet

∴ AB = 8 feet

- AC contains AB and BC

∵ AC = AB + BC

∴ AC = 8 + 8 = 16

∵ AC = CD

∵ AC = 16

∴ CD = 16

- AD contains AC and CD

∵ AD = AC + CD

∴ AD = 16 + 16 = 32

The length of AD is 32 feet

Learn more:

You can learn more about the mid-point in brainly.com/question/3269852

#LearnwithBrainly

3 0

4 years ago

Dual-energy X-ray absorptiometry (DXA) is a technique for measuring bone health. One of the most common measures is total body b

sesenic [268]

Answer:

$\bar d=\frac{\sum_{i=1}^n d_i}{n}=-0.001$

$s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}=0.0095$

-The sample is too small to make judgments about skewness or symmetry.

H0: $\mu_{1}=\mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

$t=\frac{1.173-1.174}{\sqrt{\frac{0.1506^2}{8}+\frac{0.1495^2}{8}}}=-0.013$

$p_v =2*P(t_{(14)}$

So the p value is a very high value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and a we don't have a significant difference between the two means.

Step-by-step explanation:

First we need to find the difference defined as:

(Operator 1 minus Operator 2)

d1=1.326-1.323=0.003 d2=1.337-1.322=0.015

d3=1.079-1.073=0.006 d4=1.229-1.233=-0.004

d5=0.936-0.934=0.002 d6=1.009-1.019=-0.01

d7=1.179-1.184=-0.005 d8=1.289-1.304=-0.015

Now we can calculate the mean of differences given by:

$\bar d=\frac{\sum_{i=1}^n d_i}{n}=-0.001$

And for the sample deviation we can use the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}=0.0095$

Describe the distribution of these differences using words. (which one is correct)

We can plot the distribution of the differences with the folowing code in R

differences<-c(0.003,0.015,0.006,-0.004,0.002,-0.01,-0.005,-0.015)

hist(differences)

And we got the image attached. And we can see that the distribution is right skewed but we don't have anough info to provide a conclusion with just 8 differnences.

-The sample is too small to make judgments about skewness or symmetry.

Use a significance test to examine the null hypothesis that the two operators have the same mean. Give the test statistic. (Round your answer to three decimal places.)

$\bar X_{1}=1.173$ represent the mean for the operator 1

$\bar X_{2}=1.174$ represent the mean for the operator 2

$s_{1}=0.1506$ represent the sample standard deviation for the operator 1

$s_{2}=0.1495$ represent the sample standard deviation for the operator 2

$n_{1}=8$ sample size for the operator 1

$n_{2}=8$ sample size for the operator 2

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the means for the two groups are the same, the system of hypothesis would be:

H0: $\mu_{1}=\mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We can replace in formula (1) like this:

$t=\frac{1.173-1.174}{\sqrt{\frac{0.1506^2}{8}+\frac{0.1495^2}{8}}}=-0.013$

Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test. The first step is calculate the degrees of freedom, on this case:

$df=n_{1}+n_{2}-2=8+8-2=14$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{(14)}$

So the p value is a very high value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and a we don't have a significant difference between the two means.

8 0

3 years ago

How do i calculate root equations

WITCHER [35]

It by root you mean radical equations, well then I can’t help you there, as there is too much stuff to cover.

If you mean zeros, then to find the root of a function you just find the zeros.

7 0

3 years ago

Nicholas wrote the steps below to simplify the fraction 20/30 find his error and correct it

Dmitrij [34]

Unfortunately, Nicholas' steps in simplifying the fraction is not reflected in the question. However, the general idea of the simplifying fraction is to find the greatest common factor (GCF) of both the numerator and the denominator. In this case, the GCF is 10. Then, divide both numbers by the GCF. The answer for this item should be 2/3.

7 0

3 years ago

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