I believe the correct answer is antioxidant. An antioxidant is a substance that protects vulnerable molecules from free radicals. Antioxidants<span> are man-made or natural substances that may prevent or delay some types of cell damage due to free radicals.</span>
Answer:
2.29 m.
Explanation:
The following data were obtained from the question:
Mass of KOH = 42.3 g
Molar mass of KOH = 56.11 g/mol
Mass of water = 329 g
Molality of KOH = ?
Next, we shall determine the number of mole in 42.3 g of KOH. This can be obtained as follow:
Mass of KOH = 42.3 g
Molar mass of KOH = 56.11 g/mol
Mole of KOH =?
Mole = mass /Molar mass
Mole of KOH = 42.3/56.11
Mole of KOH = 0.754 mole
Next, we shall convert 329 g of water to kilogram (kg). This can be obtained as follow:
1000 g = 1 kg
Therefore,
329 g = 329 g /1000 g × 1 kg
329 g = 0.329 kg
Therefore, 329 g of water is equivalent to 0.329 kg
Finally, we shall determine the molality of the KOH solution ad follow:
Molality is defined as the mole of solute per unit kilogram of solvent (water) i.e
Molality = mole/ mass (kg) of water
Mole of KOH = 0.754 mole.
Mass of water = 0.329 kg.
Molality = mole/ mass (kg) of water
Molality = 0.754/0.329
Molality = 2.29 m
Therefore, the molality of the KOH solution is 2.29 m.
Here we have to choose the specific iron ion preset in the compound FeO among the given ions.
The iron ion present in FeO is iron (II) ion.
The compound FeO is a neutral compound. Where the anion is oxide ion (O²⁻) thus the cation should also contain two unit positive charge. Thus Fe²⁺. Hence , the iron ion is Fe (II) ion.
The ferride ion means Fe²⁻ ion which cannot be present in FeO as the anion is already present which is O²⁻.
The iron (I) ion means iron present in +1 state, then to neutralize the compound 2 iron (I) is needed but in compound FeO there is only one iron present. Thus it cannot be iron (I) ion.
The ferride (I) ion means Fe¹⁻, which cannot be the state of the iron in FeO as there already present an anion which is O²⁻ ion.