Answer : The value of equilibrium constant (K) is, 424.3
Explanation : Given,
Concentration of 
at equilibrium = 0.067 mol
Concentration of 
at equilibrium = 0.021 mol
Concentration of 
at equilibrium = 0.040 mol
The given chemical reaction is:
The expression for equilibrium constant is:
![K_c=\frac{[CH_3OH]}{[CO][H_2]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3OH%5D%7D%7B%5BCO%5D%5BH_2%5D%5E2%7D)
Now put all the given values in this expression, we get:
Thus, the value of equilibrium constant (K) is, 424.3
Answer:
1.0 *10^(-4) mol
Explanation:
For gases:
n1/n2 = V1/V2
n1/3.8*10^(-4) mol = 230 mL/ 860 mL
n1 = 3.8*10^(-4)*230/860 = 1.0 *10^(-4) mol
Answer:
To break down the nucleus of an atom
Explanation:
Remember to change from one element to another, is necessary to add protons, neutrons and electrons,in most of the cases.
The take an electron from an atom you need certain energy, but they are in the outside part of the atom so is not as much energy as the one is necessary to take one neutron or proton from the inside part of an atom.
In this way, is a must to have a combination of pressure and heat to destabilize an atom and take some of this subatomic particles.
Answer:
snetence
Explanation:
nikkak youk dxmbk aslk istgk
Answer:
V = 15 L
Explanation:
PV = nRT
P = 1.29 atm, T= 355 K mass argon 40g/mol
n = mass/ molecular mass; n = 26.6 g/40 g/mol; n = 0.665 mol
V = (0,665 mol x 0.082 x 355 K) / 1.29 atm = 15 L
