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Dmitriy789 [7]
3 years ago
13

Check all the true statements concerning two identical containers, one with helium gas in it and one with xenon gas. Choose one

or more:
a. When the temperature of either sample of gas increases, the root-mean-square speed increases.
b. If both gases are at the same temperature, they have the same average kinetic energy.
c. When the temperature of either sample of gas increases, the number of particles with average kinetic energy increases.
d. If both of the containers are at the same temperature, they will have the same root-mean-square speed.
Chemistry
1 answer:
Allisa [31]3 years ago
7 0

Answer:

The answers to the question are as follows

a. True

b. True

c. True

d. false

Explanation:

The requiredrelation is

u_{rms}  = \sqrt{\frac{3RT}{m} }

Where R = The gas constant

T =  the temperature in kelvin

m = molecular mass

u_{rms} = root mean square speed

From the above relation on the kinetic energy of a gas we have the following true statements

a. When the temperature of either of the sample of gas increases, the root-mean-square speed increases.

This statement is true as the root means square velocity is directly proportional to the square root of the temperature a. is true

b. If both gases are at the same temperature, they have the same average kinetic energy.

From the equation for the average kinetic energy KE_{avg}  = \frac{3}{2} RT we see that the kinetic energy is directly proportional to its Kelvin temperature and  hence b. is true

c. When the temperature of either sample of gas increases, the number of particles with average kinetic energy increases.

This statement is true as shown in the kinetic energy equation

d. If both of the containers are at the same temperature, they will have the same root-mean-square speed.

This statement is false as xenon and helium have different, molecular masses

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Explanation:

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Equilibrium will lie to the right.

Explanation:

K_{a}(HF)> K_{a}(C_{6}H_{5}COOH)

That means HF is stronger acid than C_{6}H_{5}COOH.

Alternatively, it can be said that C_{6}H_{5}COO^{-} is a stronger base than F^{-}.

Therefore HF readily gives proton to C_{6}H_{5}COO^{-} to form C_{6}H_{5}COOH and F^{-} than the reverse reaction.

So, the equilibrium will lie more towards the right i.e. towards formation of C_{6}H_{5}COOH and F^{-}.

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Answer : The formal charge on the central nitrogen atom is, (+1)

Explanation :

Resonance structure : Resonance structure is an alternating method or way of drawing a Lewis-dot structure for a compound.

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First we have to determine the Lewis-dot structure of CNO^-.

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, CNO^-

As we know that carbon has '4' valence electrons, nitrogen has '5' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in CNO^- = 4 + 5 + 6 + 1= 16

According to Lewis-dot structure, there are 8 number of bonding electrons and 8 number of non-bonding electrons.

Now we have to determine the formal charge for each atom.

Formula for formal charge :

\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}

For structure 1 :

\text{Formal charge on O}=6-6-\frac{2}{2}=-1

\text{Formal charge on C}=4-2-\frac{6}{2}=-1

\text{Formal charge on N}=5-0-\frac{8}{2}=+1

For structure 2 :

\text{Formal charge on O}=6-4-\frac{4}{2}=0

\text{Formal charge on C}=4-4-\frac{4}{2}=-2

\text{Formal charge on N}=5-0-\frac{8}{2}=+1

For structure 3 :

\text{Formal charge on O}=6-2-\frac{6}{2}=+1

\text{Formal charge on C}=4-6-\frac{2}{2}=-3

\text{Formal charge on N}=5-0-\frac{8}{2}=+1

The best Lewis-dot structure is, structure 1.

Thus, the formal charge on the central nitrogen atom is, (+1)

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