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Vadim26 [7]
3 years ago
13

What situation would give you a mechanical advantage? *

Physics
1 answer:
Salsk061 [2.6K]3 years ago
5 0

Answer:

D

Explanation:

In a fixed pulley system, there is load, carried bi the strings and also there is effort which is the number of the turns of strings <em><u>o</u></em><em><u>r</u></em> number of the wheels in the pulley system

Since

mechanical \: advantage =  \frac{load}{effort}

There is M.A in the fixed pulley system

But in other objectives, there is load but they lack effort, hence they cannot give mechanical advantage

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What is the change in internal energy of the system (∆U) in a process in which 10 kJ of heat energy is absorbed by the system an
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Answer:

Explanation:

According to first law of thermodynamics:

∆U= q + w

= 10kj+(-70kJ)

-60kJ

, w = + 70 kJ

(work done on the system is positive)

q = -10kJ ( heat is given out, so negative)

∆U = -10 + (+70) = +60 kJ

Thus, the internal energy of the system decreases by 60 kJ.

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3 years ago
How long does it take to change a flat plain into mountains? help
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Im not for sure but i think it takes a couple hundred years (or according to the climate)
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A 150 kg line backer sacks the 120 kg quarterback. With what force is the quarterback sacked if the line backer has an accelerat
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Answer:

The force required to move the quarterback with linebacker is <u>1215 N</u>

Explanation:

\text { Mass of linebacker } \mathrm{m}_{2}=150 \mathrm{kg}

\text { Mass of quarterback } \mathrm{m}_{2}=120 \mathrm{kg}

\text { Moved at an acceleration }(a)=4.5 \mathrm{m} / \mathrm{s}^{2}

Using Newton's second law, it is established that  F = Ma

Where F is net force acting on the system, a is the acceleration and M is mass of the two object \left(m_{1}+m_{2}\right)

Now consider both \mathrm{m}_{1} \text { and } \mathrm{m}_{2}as a system, so net force acting on the system is \text { Force }=\left(m_{1}+m_{2}\right) a

Substitute the given values in the above formula,

\text { Force }=(150+120) \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}

\text { Force }=270 \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}

Force = 1215 N

<u>1215 N </u>is the force required to move the quarterback with linebacker.

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3 years ago
Dona rolls a marble with a speed of 5.0/m/s across a level table that is 1.6m above the floor. Upon reaching the edge of the tab
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Answer:

2.9 m

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t = 0.571 s

Next, find the distance it travels in that time.

x = x₀ + v₀ t + ½ at²

x = (0 m) + (5.0 m/s) (0.571 s) + ½ (0 m/s²) (0.571 s)²

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the correct answer is 14m

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