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3 years ago

What situation would give you a mechanical advantage? *

Physics

1 answer:

Salsk061 [2.6K]3 years ago

5 0

Answer:

Explanation:

In a fixed pulley system, there is load, carried bi the strings and also there is effort which is the number of the turns of strings or number of the wheels in the pulley system

Since

$mechanical \: advantage = \frac{load}{effort}$

There is M.A in the fixed pulley system

But in other objectives, there is load but they lack effort, hence they cannot give mechanical advantage

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Two 20kg spheres are placed with their

Maslowich

Answer:

F = 1.07 x 10⁻⁷ N

Explanation:

The gravitational force of attraction between two objects can be found by the use of Newton's Gravitational Law:

$F = \frac{Gm_{1}m_{2}}{r^2}\\\\$

where,

F = Gravitational Force of attraction = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

m₁ = m₂ = mass of spheres = 20 kg

r = distance between the objects = 50 cm = 0.5 m

Therefore,

$F = \frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(20\ kg)(20\ kg)}{(0.5\ m)^2}\\\\$

F = 1.07 x 10⁻⁷ N

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3 years ago

Heres some earned points

egoroff_w [7]

Answer:

what do you mean by that.

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3 years ago

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On a horizontal, linear track lies a cart that has a fan attached to it. The mass of the cart plus fan is 364 g. The cart is pos

mamaluj [8]

Answer:

6.62s

Explanation:

Metric unit conversion:

364 g = 0.364 kg

789 g = 0.789 kg

Starting from rest, the cart takes 4.49 s to travel a distance of 1.43 m. We can use the following equation of motion to calculate the constant acceleration

$s = a_1t_1^2/2$

$a_1 = \frac{2s}{t_1^2} = \frac{2*1.43}{4.49^2} = 0.142 m/s^2$

Using Newton's 2nd law, we can calculate the force generated by the fan to push the 0.364 kg cart forward

$F = a_1m_1 = 0.142*0.364 = 0.052 N$

Now that more mass is added, the new acceleration of the 0.789 kg cart is

$a_2 = F/m_2 = 0.052 / 0.789 = 0.065 m/s^2$

We can reuse the same equation of motion to calculate the time it takes to travel 1.43 m from rest

$s = a_2t_2^2/2$

$t_2^2 = 2s/a_2 = 2*1.43/0.065 = 43.7$

$t_2 = \sqrt{43.7} = 6.62s$

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4 years ago

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How would a system which exchanges energy but does not exchange matter between the system and the surroundings be classified?

Elodia [21]

If a system allows the exchange of energy but does not permit exchange of matter between the system and surroundings, this system is classified as a CLOSED system. The energy that flows in and out of the system boundaries is in the form of heat.

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3 years ago

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The force that opposes the start of motion is referred to as _____.

Xelga [282]

The force that opposes the start of motion is referred to as static friction.

Friction is a force that opposes motion in general, and static friction opposes initial movement. This is because, when two objects are stopped near one another, weak bonds begin to form between the atoms on their surfaces. These bonds must be broken in order for one object to move away from the other. This resistance caused by the bonds between motionless objects is static friction.

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3 years ago