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Arada [10]
3 years ago
9

How would a system which exchanges energy but does not exchange matter between the system and the surroundings be classified?

Physics
2 answers:
Elodia [21]3 years ago
4 0
If a system allows the exchange of energy but does not permit exchange of matter between the system and surroundings, this system is classified as a CLOSED system. The energy that flows in and out of the system boundaries is in the form of heat. 
Margaret [11]3 years ago
4 0

Explanation:

When a system exchanges only energy and there is no exchange of matter between the system and surrounding then this means the system is closed.

For example, when we placed hot water in a closed jar then after a certain hours the water inside the container becomes cold. This is because energy in the form of heat has been exchanges with the atmosphere or surroundings.

Hence, there is no exchange of matter between the system and surrounding.

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5 0
4 years ago
Describe how positive and negatives pairs will react?
oksian1 [2.3K]
Positive will react better together. But opposites will try to get as far away as possible.
6 0
3 years ago
If the car passes point A with a speed of 20 m/s and begins to increase its speed at a constant rate of at = 0.5 m/s2 , determin
IceJOKER [234]

Answer:

1.68 \frac{m}{s^2}

Explanation:

Please find the image for the question as attached file.

Solution -

Given -

First of all we will calculate the velocity at point C,

As per newton's third law of motion-

V_C^2 = V_A^2 + 2 a_t (S_C - S_A)\\

Substituting the given values in above equation, we get -

V_C^2 = 20^2 + 2*0.5*(100-0)\\V_C = 22.361 \frac{m}{s}

Now we will determine the radius of curvature for the curve shown in the attached image

Y = 16 - \frac{1}{625} X^2\\

Differentiating on both the sides, we get -

\frac{dy}{dx} = -3.2 (10^-3) X\\\frac{d^2y}{d^2x} =  -3.2 (10^-3)\\Curve = \frac{[1+(\frac{dy}{dx})^2]^{\frac{3}{2}}  }{\frac{d^2y}{d^2x}} \\Curve = 312.5meter

Acceleration on curved path

a = \frac{V_C^2}{Curve} \\a = \frac{22.361^2}{312.5} \\a= 1.60 \frac{m}{s^2}

Final acceleration

a_f = \sqrt{0.5^2 + 1.6^2} \\a_f = 1.68\frac{m}{s^2}

5 0
3 years ago
How many significant digits should the answer to the following problem have? (2.49303 g) * (2.59 g) / (7.492 g) =
Feliz [49]

The number of significant digits to the answer of the following problem is four.

<h3>What are the significant digits?</h3>

The number of digits rounded to the approximate integer values are called the significant digits.

The following problem is

(2.49303 g) * (2.59 g) / (7.492 g) =

On solving we get

= 0.86184566204

The answer is approximated to  0.86185

Thus, the significant digits must be four.

Learn more about significant digits.

brainly.com/question/1658998

#SPJ1

6 0
2 years ago
A golf club experts an average force of 475 N for 0.006 seconds when it collides with a golf ball on a tee. What is the impulse
Ainat [17]

Answer: 2.85 N.s

Explanation: Impulse is the product of force and time or expressed in the following formula:

J = F x t

= 475 N x 0.006 s

= 2.85 N.s

8 0
3 years ago
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