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3 years ago

How would a system which exchanges energy but does not exchange matter between the system and the surroundings be classified?

2 answers:

4 0

If a system allows the exchange of energy but does not permit exchange of matter between the system and surroundings, this system is classified as a CLOSED system. The energy that flows in and out of the system boundaries is in the form of heat.

Margaret [11]3 years ago

4 0

Explanation:

When a system exchanges only energy and there is no exchange of matter between the system and surrounding then this means the system is closed.

For example, when we placed hot water in a closed jar then after a certain hours the water inside the container becomes cold. This is because energy in the form of heat has been exchanges with the atmosphere or surroundings.

Hence, there is no exchange of matter between the system and surrounding.

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A pickup truck is traveling down the highway at a steady speed of 30.1 m/s. The truck has a drag coefficient of 0.45 and a cross

Sav [38]

Answer:

The energy that the truck lose to air resistance per hour is 87.47MJ

Explanation:

To solve this exercise it is necessary to compile the concepts of kinetic energy because of the drag force given in aerodynamic bodies. According to the theory we know that the drag force is defined by

$F_D=\frac{1}{2}\rhoC_dAV^2$

Our values are:

$V=30.1m/s$

$C_d=0.45$

$A=3.3m^2$

$\rho=1.2kg/m^3$

Replacing,

$F_D=\frac{1}{2}(1.2)(0.45)(3.3)(30.1)^2$

$F_D=807.25N$

We need calculate now the energy lost through a time T, then,

$W = F_D d$

But we know that d is equal to

$d=vt$

Where

v is the velocity and t the time. However the time is given in seconds but for this problem we need the time in hours, so,

$W=(807.25N)(30.1m/s)(3600s/1hr)$

$W=87.47*10^6J$ (per hour)

Therefore the energy that the truck lose to air resistance per hour is 87.47MJ

4 0

3 years ago

The turnbuckle is tightened until the tension in the cable AB equals 2.3 kN. Determine the vector expression for the tension T a

brilliants [131]

Answer:

a) 0.83984 i + 0.41992 j - 2.0996 k KN

b) T_ac = 1.972888 KN

Explanation:

Given:

- The tension in cable AB = 2.3 KN

Find:

a) Determine the vector expression for the tension T as a force acting on member AD.

b) Also find the magnitude of the projection of T along the line AC.

Solution:

part a)

- Find unit vector AB:

vector (AB) = 2 i + j - 5 k

mag (AB) = sqrt (2^2 + 1^2 + 5^2)

mag (AB) = sqrt(30)

unit (AB) = ( 1 / sqrt(30) )* ( 2 i + j - 5 k )

- Find Tension vector:

vector (T) = unit(AB)* 2.3 KN

= 0.83984 i + 0.41992 j - 2.0996 k

- The projection of T onto AC can be found from the dot product of vector T to unit vector (AC)

- For unit vector (AC)

vector (AC) = 2 i - 2 j - 5 k

mag (AC) = sqrt (2^2 + 2^2 + 5^2)

mag (AC) = sqrt(33)

unit (AC) = ( 1 / sqrt(33) )* ( 2 i - 2 j - 5 k )

- Compute the projection:

T_ac = vector T . unit (AC)

T_ac = (0.83984 i + 0.41992 j - 2.0996 k) . ( 1 / sqrt(33) )* ( 2 i - 2 j - 5 k )

T_ac = 0.2923947572 - 0.146973786 - 1.827467232

T_ac = 1.972888 KN

4 0

3 years ago

1. What charge is stored in a 180.0-μFcapacitor when 120.0 V is applied to it?

marin [14]

Answer:

So capacitance is charge divided by voltage and we can multiply both sides by V to solve for Q. So Q—the charge stored in the capacitor—is the capacitance multiplied by the voltage. So it's 180 times 10 to the minus 6 farads times 120 volts which is 0.0216 coulombs.

Explanation:

3 0

3 years ago

10). Three - fourth of the volume of a block which is floating in water extends above the surface

ikadub [295]

Answer:

Explanation:

Fill the graduated cylinder partially with water to a level where you can submerge the object and drop the sinker weight into the water. If you don't have a graduated cylinder to fit your object, put a cylinder in a basin, fill it to the top with water and measure the overflow into the basin. Your answer will be less accurate because of the number of times the water has been moved. Note the amount of displacement in milliliters (ml) caused by the sinker and string.

Measure the mass of your object (say a cork) on a balance scale in grams (g). Be sure the object is dry when it is measured. Record its weight. Attach the sinker with the string to the object. If you use a staple or pin, be sure to include that when you measure the displacement of the sinker in step one.

5 0

3 years ago

ANSWER IN LESS THAN A MIN!! EASY!!

snow_lady [41]

Answer:

I think they are both equal in strength but make sure from others

7 0

3 years ago

Read 2 more answers