Answer:
a. P1=200235pa
b. h=26.91m
Explanation:
The main water line enters a house on the first floor. The line has a gauge pressure of 2.64 x 105 Pa.
(a) A faucet on the second floor, 6.50 m above the first floor is turned off. What is the gauge pressure at this faucet?
(b) How high could a faucet be before no water would flow from it, even if the faucet were open?
pressure is the force per unit area.
force is that which tends to change a boy's state of rest or uniform motion in a straight line
rho stands for the density of water which is 1000kg/m3
p2=p1+rhogh
p1=p2-rhogh
the gauge pressure at 6.5m
will be:
2.64 x 10^5 Pa-100kg/m3*9.81*6.5
P1=200235pa
b. How high could a faucet be before no water would flow from it, even if the faucet were open?
b.h=p2-p1/(grho)
h=2.64 x 105 Pa/(1000*9.81)
h=26.91m
