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SOVA2 [1]
3 years ago
15

Leroy guesses that there are 150 Skittles in a jar. The actual amount is 175. Find the percent change round to the nearest tenth

.
NEED THIS URGENTLY
you dont understand how sus I look on my test
Mathematics
2 answers:
saul85 [17]3 years ago
7 0
6/7 or 85.71%
Dont get voted out of the class
Butoxors [25]3 years ago
7 0
6/5 hope thjs help s
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laila [671]

Answer:

x + x + 4 + 3x - 9 =90  \\ 5x = 95 \\ x = 19 \\  \\ gjh = 19 + 4 = 23

8 0
3 years ago
Can you answer those questions
alexandr402 [8]

Step-by-step explanation:

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7 0
3 years ago
Last question was wrong. Line l and line m are straight lines. What is the measure of angle y?
mafiozo [28]

y+43°= 180°( straight angle)

=>y= 180°-43°

=>y=137°

7 0
3 years ago
Read 2 more answers
xYou volunteer to help drive children at a charity event to the​ zoo, but you can fit only 6 of the 16 children present in your
brilliants [131]

There are 8008 groups in total, in other to drive the children

<h3>How to determine the number of groups?</h3>

From the question, we have

  • Total number of children, n = 16
  • Numbers to children at once, r = 6

The number of group of children that could be carried at once is calculated using the following combination formula

Total = ⁿCᵣ

Where

n = 16 and r = 6

Substitute the known values in the above equation

Total = ¹⁶C₆

Apply the combination formula

ⁿCᵣ = n!/(n - r)!r!

So, we have

Total = 16!/10!6!

Evaluate

Total = 8008

Hence, the number of groups is 8008

Read more about combination at

brainly.com/question/11732255

#SPJ1

8 0
1 year ago
help The screen in a theatre is 22 ft high and is positioned 10 ft above the floor, which is flat. The first row of seats is 7 f
Stella [2.4K]
 <span>(a.) 
Let's say α is the angle that subtends from the top of the screen to horizontal eye-level. 
Let β be the angle that subtends from the bottom of the screen to horizontal eye-level. 

tanα = (22 + 10 - 4) / x = 28/x 
α = arctan(28/x) 

tanβ = (10 - 4) / x = 6/x 
β = arctan(6/x) 

Ɵ = α - β 
Ɵ = arctan(28/x) - arctan(6/x) 

(b.) 
tanƟ = tan(α - β) = (tanα - tanβ) / (1 + tanα tanβ) 
tanƟ = (28/x - 6/x) / [1 + (28/x)(6/x)] 
tanƟ = (22/x) / [1 + (168/x²)] 
tanƟ = 22x / (x² + 168) 
Ɵ = arctan[22x / (x² + 168)]</span>
4 0
3 years ago
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